问题描述
我写了下面的代码,它显示了 sqlite3.OperationalError:数据库被锁定
错误。任何调试帮助都将不胜感激。
I have written the following code, which is showing the sqlite3.OperationalError: database is locked
error. Any help to debug would be much appreciated.
基本上,我正在尝试将数据从table1复制到table2,并根据table1发生的更改将数据插入到table2中一些其他的应用程序。
看起来我错过了一些。
import sqlite3
conn = sqlite3.connect("/home/sid/.Skype/testmasterut/main.db")
cursor = conn.cursor()
createLogTableSql = """create table IF NOT EXISTS sid_log as select id as "s_id",author as "s_author",timestamp as "s_timestamp",edited_by as "s_editedby",edited_timestamp as "s_edited_timestamp",body_xml as "s_body_xml" from Messages"""
cursor.execute(createLogTableSql)
conn.commit()
print "Table to save the old messages has been created"
selectLog = """ select * from sid_log """
original_table = cursor.execute(selectLog)
cursor2 = conn.cursor()
cursor3 = conn.cursor()
cursor4 = conn.cursor()
InsertTest = """ insert or ignore into sid_log (s_id,s_author,s_timestamp,s_editedby,s_edited_timestamp,s_body_xml)
select id,author,timestamp,edited_by,edited_timestamp,body_xml from Messages where id not in (select s_id from sid_log where s_id = id) and edited_by is NULL and edited_timestamp is NULL
"""
EditedTest = """ select * from Messages where id in (select s_id from sid_log where s_id = id) and edited_by is not NULL and edited_timestamp is not NULL"""
conn.close()
while True:
conn2 = sqlite3.connect("/home/sid/.Skype/testmasterut/main.db",timeout=3)
conn2.execute(InsertTest)
print "Total number of rows changed:", conn.total_changes
EditedTest2 = """ select * from Messages where id in (select s_id from sid_log where s_id = id) and edited_by is not NULL and edited_timestamp is not NULL"""
edited_list = conn2.execute(EditedTest2)
conn2.commit()
conn2.close()
# for row in edited_list:
# queryString = "SELECT * FROM sid_log WHERE s_id IN (%s)" % str(row[0])
# original_message = conn.execute(queryString)
# for org_row in original_message:
# print "Message edited from", org_row[5], "to", row[5]
修改
以下是追溯
EditBelow is the traceback
Traceback (most recent call last):
File "try2.py", line 28, in <module>
conn2.execute(InsertTest)
sqlite3.OperationalError: database is locked
推荐答案
我不知道这是否会帮助任何人,但我想出了一个解决我自己的锁定数据库问题的解决方案。
I'm not sure if this will help anyone, but I figured out a solution to my own Locked Database problem.
使用PyCharm,发现我正在处理的脚本的几个实例都在运行。这通常是由于我正在测试的代码中的错误,但它保持活动状态(因此与db的连接仍然活动)。关闭它们(停止所有进程),再试一次 - 它每次都为我工作!
I use PyCharm and found that several instances of the script I was working on were all running. This was usually due to errors in the code I was testing, but it stayed active (and therefore the connection to the db was still active). Close out of those (stop all the processes) and try again - it has worked every time for me!
如果有人知道一段时间后超时的方法请评论这个解决方案。我试过 cur.execute(PRAGMA busy_timeout = 30000)
(从类似问题的另一个线程中找到),但似乎没有做任何事情。
If anyone knows a way to make it timeout after a little while, please comment this solution. I tried cur.execute("PRAGMA busy_timeout = 30000")
(found from another thread on a similar question) but it didn't seem to do anything.
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