从ArrayList中删除偶数

问题描述

我必须创建一个有ArrayList的方法;我需要从这个ArrayList中删除偶数。我已经写了代码，但有一个逻辑错误，我不能确定。

I have to create a method which has an ArrayList; I need to remove even numbers from this ArrayList. I have written code for that but there is a logical error which I couldn't identify.

这是我的代码：

static void sortList(){

   List <Integer> number=new ArrayList <Integer>();

   number.add(11);
   number.add(45);
   number.add(12);
   number.add(32);
   number.add(36);

   System.out.println("Unsorted List: "+number);

   for (int i=0;i<number.size();i++){      
       int even=number.get(i)%2;       
        if (even==0){
            System.out.println("This is Even Number:"+ number.get(i));
            number.remove(i);
        }    
    }

    Collections.sort(number);
    System.out.println("Sorted List: "+number);

 }

代码的输出是：

Unsorted List: [11, 45, 12, 32, 36]
This is Even Number:12
This is Even Number:36
Sorted List: [11, 32, 45]

为什么32不捕获为偶数，因为它是一个偶数，我测试然后通过使用不同的偶数在相同的位置，但结果是相同的。为什么在索引（3）它的发生，任何偶数不能被捕获。我真的想知道为什么。

I am wondering that why 32 is not caught as an Even number as it is an even number, I tested then by using different even numbers at same position but the result is same. Why at index(3) its happening that any even number couldnt be catch. I am really wondering why. So please any one can help me out for this and is there any other better way to implement this solution.

感谢

推荐答案

使用。它有一个 remove（）方法，你需要。

List<Integer> numbers = new ArrayList<Integer>();

numbers.add(11);
numbers.add(45);
numbers.add(12);
numbers.add(32);
numbers.add(36);

System.out.println("Unsorted List: " + numbers);

for (Iterator<Integer> iterator = numbers.iterator(); iterator.hasNext();) {
    Integer number = iterator.next();
    if (number % 2 == 0) {
        System.out.println("This is Even Number: " + number);
        iterator.remove();
    }

}

Collections.sort(numbers);
System.out.println("Sorted List: " + numbers);

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