本文介绍了xx时间之前的功能不起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试在聊天中显示"{number} {time-time}前".但是,当我期望"2分钟前"之类的东西时,我会看到"45年".
I am trying to display "{number} {unit-of-time} ago" in my chat. However, when I'm expecting something like "2 minutes ago", I see "45 years" instead.
没人回答吗?
以下是脚本:
<?php
$con = mysql_connect("localhost", "user", "pword");
mysql_select_db('chat', $con);
$result1 = mysql_query("SELECT * FROM logs ORDER BY id ASC");
$tm = mysql_query("SELECT timestamp FROM logs ORDER BY id ASC");
function _ago($tm, $rcs = 0)
{
$cur_tm = time();
$dif = $cur_tm - $tm;
$pds = array('second', 'minute', 'hour', 'day', 'week', 'month', 'year');
$lngh = array(1, 60, 3600, 86400, 604800, 2630880, 31570560);
for ($v = sizeof($lngh) - 1; ($v >= 0) && (($no = $dif / $lngh[$v]) <= 1); $v--) ;
if ($v < 0) $v = 0;
$_tm = $cur_tm - ($dif % $lngh[$v]);
$no = floor($no);
if ($no <> 1) $pds[$v] .= 's';
$x = sprintf("%d %s ", $no, $pds[$v]);
if (($rcs == 1) && ($v >= 1) && (($cur_tm - $_tm) > 0)) $x .= time_ago($_tm);
return $x;
}
$timeagochat = _ago($tm, $rcs = 0);
while ($extract = mysql_fetch_array($result1)) {
echo "<p class='show_message'><span class='uname'>" . $extract['username'] . "</span> <span class='time'>" . $timeagochat . " </span><br><span class='msg'>" . $extract['msg'] . "</span></p><br>";
}
?>
我该怎么做才能使此功能正常工作?
What can I do to let this function work?
推荐答案
-
您必须获取日期:
You have to fetch the date:
$tm = mysql_query("SELECT timestamp AS t FROM logs ORDER by id ASC")->fetch_assoc()['t']; //obviously, check the size before you fetch
您可能想使用strtotime()
,例如:
$dif = $cur_tm-strtotime($tm);
$dif
将以毫秒为单位.
您对循环和数组做什么?太混乱了.
What are you doing with the loops and the arrays? Too confusing.
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