使用PyQt4 QWidget显示/隐藏？

问题描述

你好，伙计们。我被困在这里 - 仍在学习OOP和Python。



我如何构建这个程序，以便我能够在启动时生成一个QWidget对象？此外，我如何制作它，以便每次点击系统托盘图标（即mediaIcon.png）时，相同的小部件不会重新实例化自己，而是每隔一次点击显示/隐藏自己？



截至目前，当我点击图标时，程序回声点击。然后关闭我不知道为什么会这样。



非常感谢，

Akratix

Hello again, guys. I'm stuck here -- still learning OOP and Python.

How do I structure this program so that I am able to spawn a QWidget object on start-up? Moreover, how do I make it so that each time I click on the System Tray Icon (namely mediaIcon.png), that same widget will not re-instantiate itself but, rather, show/hide itself with every other click?

As of right now, when I click on the icon, the program echos "Clicked." then closes. I don't know why that is.

Thanks a bunch,
Akratix

#!/usr/bin/python

import sys, os
from PyQt4 import QtGui, QtCore

class MediaFeed(QtGui.QSystemTrayIcon):

    def __init__(self, icon, parent=None):
        QtGui.QSystemTrayIcon.__init__(self, icon, parent)

        menu = QtGui.QMenu()

        aboutAction = menu.addAction("About")
        aboutAction.triggered.connect(self.aboutMenu)

        exitAction = menu.addAction("Exit")
        exitAction.triggered.connect(QtGui.qApp.quit)

        self.setContextMenu(menu)
        self.activated.connect(self.systemIcon)

    def aboutMenu(self):
        print "This should be some information."

    def systemIcon(self, reason):
        w = QtGui.QWidget()
        if reason == QtGui.QSystemTrayIcon.Trigger:
            print "Clicked."
            w.show()


def main():

    app = QtGui.QApplication(sys.argv)
    mediaFeed = MediaFeed(QtGui.QIcon("mediaIcon.png"), None)

    mediaFeed.show()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

推荐答案

这篇关于使用PyQt4 QWidget显示/隐藏？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！