本文介绍了如果Internet或信号中断,如何捕获异常的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在与媒体播放器和音频流一起工作,我想知道如果互联网或信号中断并且无法再流音频,那么捕获异常的最佳方法是什么.

i am working with mediaplayer and streaming audio and i am wondering what is the best way to catch an excpetion if the internet or signal is down and can not stream anymore audio.

下面是我到目前为止已完成的代码,如您所见,我正在用相同的消息抛出所有例外.

below is my code that i have done so far, as you can see i am throwing all the excpetion with same message.

private class taskDoSomething extends AsyncTask<Void, Void, List<Employee>>
{

    @Override
    protected List<Employee> doInBackground(Void... params)
    {
    String url = "http://ofertaweb.ro/android/sleepandlovemusic/list_files.php";

    try {
        Get_Webpage obj = new Get_Webpage(url);
        directory_listings = obj.get_webpage_source();
    } catch (Exception e) {
         Toast.makeText(this, "You have to be connected to the internet for this application to work", Toast.LENGTH_LONG).show();
       finish();
    }
}

推荐答案

它不是例外,但会检查连接

its not a exception but it checks the connection

public boolean isOnline() {
        ConnectivityManager cm = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo netInfo = cm.getActiveNetworkInfo();
        if (netInfo != null && netInfo.isConnectedOrConnecting()) {
            return true;
        }
        return false;
    }

这篇关于如果Internet或信号中断,如何捕获异常的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

05-29 02:45