本文介绍了术语中的错误.formula(formula):'.'在公式中,没有“数据"参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试使用神经网络进行预测.
I'm tring to use neuralnet for prediction.
创建一些X:
x <- cbind(seq(1, 50, 1), seq(51, 100, 1))
创建Y:
y <- x[,1]*x[,2]
给他们起个名字
colnames(x) <- c('x1', 'x2')
names(y) <- 'y'
制作data.frame:
Make data.frame:
dt <- data.frame(x, y)
现在,我遇到了错误
model <- neuralnet(y~., dt, hidden=10, threshold=0.01)
例如,在lm(线性模型)中,此方法有效.
For example, in lm(linear model) this is worked.
推荐答案
正如我的评论所述,这看起来像是非导出函数neuralnet:::generate.initial.variables
中的错误.解决方法是,只需根据dt
的名称构建一个长公式,但不包括y
,例如
As my comment states, this looks like a bug in the non-exported function neuralnet:::generate.initial.variables
. As a work around, just build a long formula from the names of dt
, excluding y
, e.g.
n <- names(dt)
f <- as.formula(paste("y ~", paste(n[!n %in% "y"], collapse = " + ")))
f
## gives
> f
y ~ x1 + x2
## fit model using `f`
model <- neuralnet(f, data = dt, hidden=10, threshold=0.01)
> model
Call: neuralnet(formula = f, data = dt, hidden = 10, threshold = 0.01)
1 repetition was calculated.
Error Reached Threshold Steps
1 53975276.25 0.00857558698 1967
这篇关于术语中的错误.formula(formula):'.'在公式中,没有“数据"参数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!