问题描述
我试图在开始时将一个字节数组插入另一个字节数组.这是我要完成的工作的简单示例.
I'm trying to insert one byte array into another at the beginning. Here's a simple example of what I'm trying to accomplish.
import struct
a = bytearray(struct.pack(">i", 1))
b = bytearray(struct.pack(">i", 2))
a = a.insert(0, b)
print(a)
但是,此操作失败并显示以下错误:
However this fails with the following error:
a = a.insert(0, b)
TypeError: an integer is required
推荐答案
bytearray
是序列类型,它支持基于切片的操作.带有切片的在位置i
插入"惯用法像这样的x[i:i] = <a compatible sequence>
.因此,对于拳头位置:
bytearray
is a sequence-type, and it supports slice-based operations. The "insert at position i
" idiom with slices goes like this x[i:i] = <a compatible sequence>
. So, for the fist position:
>>> a
bytearray(b'\x00\x00\x00\x01')
>>> b
bytearray(b'\x00\x00\x00\x02')
>>> a[0:0] = b
>>> a
bytearray(b'\x00\x00\x00\x02\x00\x00\x00\x01')
对于第三位置:
>>> a
bytearray(b'\x00\x00\x00\x01')
>>> b
bytearray(b'\x00\x00\x00\x02')
>>> a[2:2] = b
>>> a
bytearray(b'\x00\x00\x00\x00\x00\x02\x00\x01')
注意,这不等同于.insert
,因为对于序列,.insert
将整个对象插入为ith元素.因此,请考虑以下带有列表的简单示例:
Note, this isn't equivalent to .insert
, because for sequences, .insert
inserts the entire object as the ith element. So, consider the following simple example with lists:
>>> y = ['a','b']
>>> x.insert(0, y)
>>>
>>> x
[['a', 'b'], 1, 2, 3]
您真正想要的是:
>>> x
[1, 2, 3]
>>> y
['a', 'b']
>>> x[0:0] = y
>>> x
['a', 'b', 1, 2, 3]
这篇关于将bytearray插入到bytearray Python中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!