本文介绍了控制台应用程序的代码的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如果一个人x向公司支付RS1000 / - 如果x加入3个人说x1,x2,x3这三个人每个人向公司支付1000,那么x将获得该金额的10%。然后x1加入另一个3名成员说x4,x5,x6现在他们也向公司支付1000,然后x1将获得该金额的10%(即x4,x5,x6)。然后x将获得x1金额的10%。喜欢这个过程会继续。我为第一个人做这个会得到多少钱。

------------------------ -------------------------------------------------- --------------------------------------

static void main( )

{

Console.writeline(输入no.of levels);

Int l = convert.toint32(console.readline( ));

双和= 0;

For(int i = 1; i< = l; i ++)

{

Double a = math.pow(3,i);

Double b = math.pow(10,i);

Double value = 1000 * (a / b);

总和=总和+值;

}

Console.writeline(结果是+总和);

Console.readline();

}

-------------------- -------------------------------------------------- -----------------------------------------

但是我想在每个级别每个人都会得到多少钱

If a person x pays RS1000/- to a company.If x joins 3 persons say x1,x2,x3 these 3 persons each person pay 1000 to the company then x will get 10% of that amount.Then x1 joins another 3 members say x4,x5,x6 now also they pay 1000 to company then x1 will get 10% of that amount(i.e x4,x5,x6).then x will get 10% of x1 amount. like this process will continue.I do this for first person will get how much money.
----------------------------------------------------------------------------------------------------------------
staticvoid main()
{
Console.writeline("enter no.of levels");
Int l=convert.toint32(console.readline());
Double sum=0;
For(int i=1;i<=l;i++)
{
Double a=math.pow(3,i);
Double b=math.pow(10,i);
Double value=1000*(a/b);
Sum=sum+value;
}
Console.writeline("Result is "+sum);
Console.readline();
}
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But i want at each level each person will get how much money

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05-28 20:18
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