如何使用hql将参数传递给@Query注释

问题描述

这是我的hql请求：

  @Query（从a代理中选择a.visibility = true a.id desc）
 public Page< Agent> getAllAgents（可分页）; 
  

我想选择所有具有可见性的代理。

在我的Agent类中，a具有带有getVisibility和setVisibility函数的布尔可见性属性。在我的数据库可见性存储为位（1）。

我试过a.visibility = 1，... ='1'，... =' TRUE'，... ='true'，...是真的。但是我得到这个错误：

pre $ 原因：org.hibernate.hql.internal.ast.QuerySyntaxException：意外标记：近第1行，第74列[从com.GemCrmTickets.entities.Agent中选择一个，其中a.visibility = true通过a.id描述的顺序]


有什么建议吗？您的查询不正确，您有额外的 a 之间 true 和按...排序。所以正确的查询会变成这样

 从Agent中选择a a.visibility = true by a.id desc 
  

不确定是否能解决您的所有问题。检查一下。

Here is my hql requete :

@Query("select a from Agent where a.visibility = true a order by a.id desc")
public Page<Agent> getAllAgents(Pageable pageable);

I want to select all agents that have visibility true.

In my Agent class a have Boolean visibility attribute with getVisibility and setVisibility functions. In my data base "visibility" stored as bit(1).

I tried a.visibility = 1, ... = '1', ...= 'TRUE', ...='true', ... is true. But i get this error :

Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: a near line 1, column 74 [select a from com.GemCrmTickets.entities.Agent where a.visibility = true a order by a.id desc]

Any suggestions ? Thank you in advance.

解决方案

Your query is not correct, you have an extra a between true and order by.... So the correct query would become like this

select a from Agent a where a.visibility = true order by a.id desc

Not sure if that fixes all your troubles. Check it out.

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