本文介绍了基于C置换发电机的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要置换生成一个简单的算法,它可以适用于简单的C语言。
I need a simple Algorithm of permutation generator which could be apply on simple C language.
推荐答案
Permutes过的数字:
Permutes over numbers:
为了做到使用每种排列,你必须挂钩到打印功能。
In order to do use each permutation, you have to hook up to the print function.
#include <stdio.h>
#include <stdlib.h>
/**
Read a number, N, from standard input and print the
permutations.
*/
void print(const int *v, const int size)
{
if (v != 0) {
for (int i = 0; i < size; i++) {
printf("%4d", v[i] );
}
printf("\n");
}
} // print
void swap(int *v, const int i, const int j)
{
int t;
t = v[i];
v[i] = v[j];
v[j] = t;
}
void rotateLeft(int *v, const int start, const int n)
{
int tmp = v[start];
for (int i = start; i < n-1; i++) {
v[i] = v[i+1];
}
v[n-1] = tmp;
} // rotateLeft
void permute(int *v, const int start, const int n)
{
print(v, n);
if (start < n) {
int i, j;
for (i = n-2; i >= start; i--) {
for (j = i + 1; j < n; j++) {
swap(v, i, j);
permute(v, i+1, n);
} // for j
rotateLeft(v, i, n);
} // for i
}
} // permute
void init(int *v, int N)
{
for (int i = 0; i < N; i++) {
v[i] = i+1;
}
} // init
int main()
{
int *v = (int*) malloc(sizeof(int)*10);
init(v, 10);
permute(v, 0, 10);
free(v);
}
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