问题描述
如何获得屏幕宽度dpi?
How can I get the screen width dpi?
DisplayMetrics metrics = getResources().getDisplayMetrics();
int f = metrics.densityDpi;
// getWindowManager().getDefaultDisplay().getMetrics(metrics);
int width = metrics.widthPixels;
int dp = (int)(width / (metrics.density));
我这样做,所以假设我的密度dpi是120 ..,宽度像素是240 ..通过计算我得到240/0.75 ....所以我有320 widthdpi?
I do this, so lets assume my densitydpi is 120..and widthpixel 240..via calculation i get 240/0.75.... so I have 320 widthdpi?
但是事实并非如此....widthdpi小于320,我认为...是因为320在屏幕上出现了错误....使用120个作品.
However that's not the case....widthdpi is smaller then 320 I think...because 320 goes with me wrong in the screen.... using 120 works.
在Nexus 4上...宽度768和densitydpi 320 ...我除以768/2,然后得到384个正确的宽度密度dpi(有效)
on Nexus 4...with width 768 and densitydpi 320...I divide 768/2 and i get 384 correct width density dpi (it works)
但是在其他240、160、120密度dpi上..宽度dpi的计算似乎是错误的...
But on other ones like 240, 160, 120 density dpi..the calculation of width dpi seems wrong ...
推荐答案
px = dp * (dpi / 160)
因此
dp = px / (dpi / 160)
或等效地
dp = px * 160 / dpi
请记住,dp代表密度无关像素",即1dp在ldpi设备上的物理尺寸与xxhdpi设备上的物理尺寸相同.因此,您应该期望所有电话的宽度大约为300-400dp,并注意dp的存储桶大小:
Remember that dp stands for 'density-independent pixel' - i.e., 1dp is the same physical size on a ldpi device as it is on an xxhdpi device. Therefore you should expect all phones to have roughly ~300-400dp of width, noting the bucket sizes by dp:
- 超大屏幕至少为960dp x 720dp
- 大屏幕至少为640dp x 480dp
- 正常屏幕至少为470dp x 320dp
- 小屏幕尺寸至少为426dp x 320dp
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