包括重复项在内的两个列表的交集?

问题描述

>>>a = [1,1,1,2,3,4,4]>>>b = [1,1,2,3,3,3,4][1,1,2,3,4]

请注意，这与这个问题不同:保持重复的两个列表的 Python 交集因为即使列表 a 中有三个 1，列表 b 中也只有两个，所以结果应该只有两个.

解决方案

您可以使用 collections.Counter 用于此，当您进行交集时，它将为每个元素提供在任一列表中找到的最低计数.

from collections import Counterc = list((Counter(a) & Counter(b)).elements())

输出:

[1, 1, 2, 3, 4]

>>> a = [1,1,1,2,3,4,4]
>>> b = [1,1,2,3,3,3,4]

[1,1,2,3,4]

Please note this is not the same question as this:Python intersection of two lists keeping duplicatesBecause even though there are three 1s in list a, there are only two in list b so the result should only have two.

解决方案

You can use collections.Counter for this, which will provide the lowest count found in either list for each element when you take the intersection.

from collections import Counter

c = list((Counter(a) & Counter(b)).elements())

Outputs:

[1, 1, 2, 3, 4]

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