本文介绍了按键动作的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在设计一个基于网络的会计软件。每当用户按键时,我想打开新会计凭证。每当他/她按键时打开设置。
I'm designing a web based accounting software. I would like to open the "new accounting document" whenever the user press key for example. And open "settings" whenever he/she is pressing key.
我看到一些基于JavaScript和jQuery的脚本。但他们并没有完全奏效。有人可以帮我吗?
I saw some scripts based on JavaScript and jQuery. But they did not work exactly. Can anyone help me please ?
我试过这个剧本:
var code = (e.keyCode ? e.keyCode : e.which);
if(code == 13) { //Enter keycode
//Do something
}
推荐答案
$(document).bind('keyup', function(e){
if(e.which==78) {
// "n"
}
if(e.which==83) {
// "s"
}
});
要防止输入聚焦:
$("body").on("focus",":input", function(){ $(document).unbind('keyup'); });
$("body").on("blur",":input", function(){ $(document).bind('keyup', function(e){ etc.... });
您可能想要放置 bind
函数进入它自己的函数,所以你不重复代码。例如:
You might want to put the bind
function into its own function so you don't duplicate code. e.g:
function bindKeyup(){
$(document).bind('keyup', function(e){
if(e.which==78) {
// "n"
}
if(e.which==83) {
// "s"
}
});
}
$("body").on("focus",":input", function(){ $(document).unbind('keyup'); });
$("body").on("blur",":input", function(){ bindKeyup(); });
这篇关于按键动作的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!