问题描述
我试图创建一个php可执行文件(一个phar文件)以生成一些文件，并且我想知道如何获取phar文件的真实路径(在phar文件代码内).
I am trying to create a php executable (a phar file) for generating some files, and I would like to know how to get the real path of the phar file (within the phar file code).
我想做的是在phar文件的同一级别中创建一个文件夹，然后在其中创建新文件，但是realpath(__DIR__.'/../')似乎不起作用.
What I want to do is to create a folder in the same level of the phar file and create the new files there, but realpath(__DIR__.'/../') does not seem to work.
谢谢
推荐答案
如 https://stackoverflow.com/a/28775172/282601 __FILE__常量具有以下方案的完整路径:
As shown in https://stackoverflow.com/a/28775172/282601 the __FILE__ constant has the full path with the scheme:
phar:///home/cweiske/Dev/test/phar/test.phar/path/to/foo.php
__DIR__与之类似:
phar:///home/cweiske/Dev/test/phar/test.phar/path/to
因此，在调用realpath(__DIR__)时，您仍然具有phar://前缀，可防止您加载文件.
So when calling realpath(__DIR__) you still have the phar:// prefix that prevents you from loading the file.
您必须删除phar://方案以及.phar内部文件的路径，才能使用__DIR__获取phar位置.
You have to remove the phar:// scheme as well as the path of the file inside the .phar to get the phar location with __DIR__.
Phar::running(false) 容易得多，它只是返回路径:
Much easier is Phar::running(false), which simply returns the path:
/home/cweiske/Dev/test/phar/test.phar
这篇关于如何在phar文件代码中获取.phar文件真实目录?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！