为什么静态成员函数会那样工作?

问题描述

大家好，最近我遇到一个问题:

hello,erveryone,recently I meeted a question:

#include <iostream.h>
#include <string.h>

class MyTime
{
public:
      char m_MyName[100];
     static int m_count
      MyTime(char *p1,char *p2,int i,int j,int k);
      ~MyTime();
      void ShowTime();
     static void GetCount();
     static void GetTime(MyTime); 
protected:
       char m_MyGender[5];
private
       int m_Hour;
      int m_Minute;
      int m_Second;
};
int MyTime::m_count=0;
MyTime::MyTime(char *p1,char *p2,int i,int j,int k)
{
    strcpy(m_MyName,p1);
    strcpy(m_MyGender,p2);
    m_Hour=i;
    m_Minute=j;
    m_Second=k; 
}
void MyTime::ShowTime()
{
     cout<<m_MyName<<" tell:it is:"<<m_Hour<<":"<<m_Minute<<":"<<m_Second<<endl;
}
MyTime::~MyTime()
{
     m_Hour=m_Hour+1;
     m_Minute=m_Minute+1;
     m_Second=m_Second+1;
     ShowTime();
}
void MyTime::GetCount()
{
    cout<<"m_count="<<m_count<<endl;
}
void MyTime::GetTime(MyTime t)
{
     cout<<"time: "<<t.m_Hour<<":"<<t.m_Minute<<":"<<t.m_Second<<endl;
}

 
void main()
{
   char *p1="sunshine";
   char *p2="man";  
   MyTime mytime(p1,p2,10,10,10);
   MyTime::m_count++;
   mytime.GetCount();
   MyTime::GetTime(mytime);
 }
The result is:
m_count=1
time: 10:10:10
sunshine  tell:it is:11:11:11
sunshine  tell:it is:11:11:11
Press any key to continue</string.h></iostream.h>

刚才我很困惑为什么"sunshine tell:it is:11:11:11"出现两次.检查代码后，我发现这是〜MyTime()起作用两次的原因.当我删除该代码时"MyTime :: GetTime(mytime)"，它正常工作.
现在我不知道为什么它会那样工作，你呢?我期待着您的答复！ ^ _ ^^ _ ^^ _ ^

Just now,I was confused that why "sunshine tell:it is:11:11:11" appeared twice.After checking the code,I found it was the reason of ~MyTime(),which worked twice.And when I deleted the "MyTime::GetTime(mytime)",it worked correctly.
Now I don''t know why it works like that,And you? I''m looking forward to your answer! ^_^^_^^_^

推荐答案

static void GetTime(const MyTime & t);

(实现)

(implementation)

void MyTime::GetTime(const MyTime & t)
{
  //...
}

如果您不喜欢这样的行为.

if you don''t like such a behaviour.

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