的ExpectedException断言

问题描述

我需要编写单元测试下一个功能，我看到我可以使用[的ExpectedException]

I need to write a unit test for the next function and I saw I can use [ExpectedException]

这是要测试的功能。

public static T FailIfEnumIsNotDefined<T>(this T enumValue, string message = null)
        where T:struct
    {
        var enumType = typeof (T);

        if (!enumType.IsEnum)
        {
            throw new ArgumentOutOfRangeException(string.Format("Type {0} is not an Enum, therefore it cannot be checked if it is Defined not have defined.", enumType.FullName));
        } 
        else if (!Enum.IsDefined(enumType, enumValue))
        {
            throw new ArgumentOutOfRangeException(string.Format("{1} Value {0} is not does not have defined value in Enum of type {0}. It should not be...", enumType.FullName, message ?? ""));
        }

        return enumValue;
    }

在这里会去的代码来测试，都应该被扔例外

and here would go the code to test the exceptions that are supposed to be threw

    [TestMethod] 
    [ExpectedException(ArgumentOutOfRangeException(ArgumentException), "message")]
    public void FailIfEnumIsNotDefined_Check_That_The_Value_Is_Not_Enum()
    {
        // PREPARE
        // EXECUTE
        // ASSERT
    }

我没有想法已经作出的例外或者断言。

I don't have idea have to make the assert for the exceptions either.

推荐答案

的ExpectedException 只是断言指定类型的异常将被试验方法抛出：

ExpectedException just asserts that exception of specified type will be thrown by test method:

[TestMethod] 
[ExpectedException(typeof(ArgumentOutOfRangeException))]
public void FailIfEnumIsNotDefined_Check_That_The_Value_Is_Not_Enum()
{
    // PREPARE
    // EXECUTE
    // NO ASSERT!!
}

如果您想断言异常的其他参数，那么你应该使用在try..catch 在您的测试方法：

If you want to assert other parameters of exception, then you should use try..catch in your test method:

[TestMethod]     
public void FailIfEnumIsNotDefined_Check_That_The_Value_Is_Not_Enum()
{
    // PREPARE

    try
    {
       // EXECUTE
       Assert.Fail()
    }
    catch(Exception exception)
    {        
        // ASSERT EXCEPTION DETAILS
    }
}

---

您可以编写自己的断言异常的方法被抛出，以避免一遍又一遍的重复相同的测试代码：

---

You can write your own method for asserting exception was thrown to avoid repeating same test code over and over again:

public TException AssertCatch<TException>(Action action)
    where TException : Exception
{
    try
    {
        action();
    }
    catch (TException exception)
    {
        return exception;
    }

    throw new AssertFailedException("Expected exception of type " + 
                                    typeof(TException) + " was not thrown");
}

用法：

Usage:

var exception = AssertCatch<ArgumentOutOfRangeException>(() => /* EXECUTE */);
Assert.AreEqual("foo", exception.Message);

这篇关于的ExpectedException断言的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！