问题描述
我有一个在通用过程(GetValue)下具有两个绑定过程(GetAsScalar& GetAsList)的类型:
I have a type with two bound procedures (GetAsScalar & GetAsList) under a generic procedure (GetValue):
type, extends(TObject) :: TKeyword
character(len=:), allocatable :: fValue
contains
procedure, private :: GetAsScalar
procedure, private :: GetAsList
generic :: GetValue => &
GetAsScalar, &
GetAsList
end type TKeyword
例程签名如下:
subroutine GetAsScalar (this, value, status)
!Arguments-------------------------------------------------------------
class(TKeyword) :: this
class(*), target :: value
logical, optional :: status
!...
end subroutine GetAsScalar
subroutine GetAsList (this, value, status)
!Arguments-------------------------------------------------------------
class(TKeyword) :: this
class(*), pointer :: value(:)
logical, optional :: status
!...
end subroutine GetAsList
在内部,TKeyword对象存储一个字符串.
Internally, the TKeyword object stores a string.
如果我尝试通过以下方式使用它(波纹管),则会出现编译错误:此类型绑定的泛型子例程调用没有匹配的特定子例程"
If I try to use it in the following way (bellow), I get a compilation error: "There is no matching specific subroutine for this type bound generic subroutine call"
class(TKeyword), pointer :: key
class(*), pointer :: p(:)
allocate (integer::p(3))
!Code to read instantiate the TKeyword object
call key%GetValue(p, status)
select type (p)
type is (integer)
write (*,*) p
end select
如果我从通用关联中删除GetASScalar并将其公开,则以下代码将按预期工作:
If I remove the GetASScalar from the generic association and make it public, the following code works as expected:
class(TKeyword), pointer :: key
class(*), pointer :: p(:)
allocate (integer::p(3))
!Code to read instantiate the TKeyword object
call key%GetAsList(p, status)
select type (p)
type is (integer)
write (*,*) p
end select
在传递标量(整数,实数,字符等)时,可以毫无问题地调用GetAsScalar例程.
When passing a scalar (integer, real, character, etc), the GetAsScalar routine is called without problems.
我想知道为什么会这样.我在通用"中缺少什么,使编译器无法识别通用下的子例程?有办法使这项工作吗?与常规签名有关吗?
I would like to know why this is happening. What am I missing in this "generic thing" that makes the compiler unable to recognize my subroutine under the generic? There is a way to make this work? Would be something related with the routine signature?
我正在使用Intel Fortran 15.0.1.148
I'm using Intel Fortran 15.0.1.148
推荐答案
根据intel fortran论坛中的答案( https://software.intel.com/en-us/forums/topic/537784#comment-1809520 ),此代码应该可以正常工作,并且编译器错误可能是编译器中的一个小错误.
Acoording to answers in the intel fortran forum (https://software.intel.com/en-us/forums/topic/537784#comment-1809520), this code should work and the compiler error is probably a small bug in the compiler.
史蒂夫·莱昂内尔(Intel)将问题升级了.
An issue was escalated by Steve Lionel (Intel).
谢谢.
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