在C ++中迭代通过连续枚举值的最简单的方法

本文介绍了在C ++中迭代通过连续枚举值的最简单的方法的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！ 问题描述 在C ++中使用连续值迭代枚举的首选简单方法是什么？我发现以前的SO这个问题涉及创建自定义操作符++ 等，但这似乎过度。到目前为止，我想出的最好的是：What is the preferred simple method for iterating through an enum with contiguous values in C++? I found previous SO questions on this subject which involved creating custom operator++ etc, but this seems like overkill. So far the best I have come up with is:enum { FOO, BAR, BLECH, NUM_ENUMS} MyEnum;//for (MyEnum m = FOO; m < NUM_ENUMS; ++m) // compile error// ...//for (MyEnum m = FOO; m < NUM_ENUMS; m = m + 1) // compile error// ...for (MyEnum m = FOO; m < NUM_ENUMS; m = MyEnum(m + 1)) // OK ? ...从编码风格的角度来看，这是合理的，警告（ g ++ -Wall ... 似乎对此感到满意）？Is this reasonable from a coding style perspective and is it likely to generate warnings (g++ -Wall ... seems happy with this) ?推荐答案 这将是未定义的： MyEnum（int（NUM_ENUMS）+ 1）因为保持（4）的值将大于枚举可以表示的值（[0,3]）;由于您确保 m 严格低于 NUM_ENUMS ，可以安全地使用 MyEnum + 1）。This would have been undefined: MyEnum(int(NUM_ENUMS) + 1) because the value to hold (4) would be greater than what the enum can represent ([0, 3]); since you ensure that m is strictly lower than NUM_ENUMS it is safe to use MyEnum(m + 1).另一方面，请注意，您会遇到自定义枚举的问题，例如：On the other hand, note that you would have issues with customized enums such as:enum OtherEnum { Foo = -1, Bar = 2, Baz = 8, NUM_OTHERENUM};因此不是通用做法。我建议生成的数组迭代，代替：I would advise a generated array to iterate over instead:MyEnum const Values[] = { FOO, BAR, BLECH };请注意，它很容易从枚举的定义生成，无意义的价值（商业智慧）。Note that it is easily generated from the definition of the enum, and also avoid polluting the interface with a nonsensical value (business-wise). 这篇关于在C ++中迭代通过连续枚举值的最简单的方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！