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问题描述

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我是Cython和C ++的noob,所以我有一个关于参数传递的问题。我想避免在以下场景中传递参数的副本:

I am a noob with Cython and C++, so I have a question on argument passing. I want to avoid passing a copy of an argument in the following scenario:

# somefile.pyx
#distutils: language = c++
from libcpp.vector cimport vector

def add_one(vector[int] vect):
    cdef int i
    n = vect.size()
    for i in range(n):
        vect[i] += 1

cdef vector[int] v
for i in range(100000):
    v.push_back(i)
add_one(v) # <-- ??

我想要方法 add_one v 就地。我相信在C ++,你可以通过预先挂起参数& 来实现这一点,这意味着对指针的任何更改都传递给了pointee。这样,你不必担心传递指针或实际对象,即

I want the method add_one to just modify v "in-place." I believe in C++, you can achieve this by pre-pending the argument with &, which means that any changes to the pointer is passed to the pointee. That way, you don't have to worry about passing a pointer or the actual object, i.e.

add_one(v); # in c++

我可以在Cython中做同样的事, def add_one(vector [int] * vect)

Can I do the same in Cython, or do I have to explicitly change the arg type to a reference instead, i.e. def add_one(vector[int]* vect)?

推荐答案

找到了我自己的问题。显然,你可以通过引用传递,但是函数必须是 cdef 'ed,而不是 def 'ed。即

Found the naswer to my own question. Apparently, you can pass by reference, but the function MUST be cdef'ed, not def'ed. i.e.

# somefile.pyx
#distutils: language = c++
from libcpp.vector cimport vector

cdef void add_one(vector[int]& vect):
    cdef int i
    n = vect.size()
    for i in range(<int>n):
        vect[i] += 1

cdef vector[int] v
for i in range(100000):
    v.push_back(i)
add_one(v)

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09-06 10:27