本文介绍了通用类中的java通用转换的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧! 问题描述 我在写一个通用的最大堆的简单实现。如果我写了 public class FastMaxHeap< T> { T [] data; int size; static final int HEAP_SIZE = 10000; @SuppressWarnings(unchecked) public FastMaxHeap(){ data =(T [])new Object [HEAP_SIZE]; size = 0; } } 编译。现在要实际实现堆,即写入maxHeapify(),我需要能够比较两个T。先验似乎是可能的一种选择是告诉编译器T实现了Comparable。但是,如果我键入替换< T>与编译器抱怨 - 我该怎么做? 或者,我可以定义一个类 public class HasValue { int value; 公共HasValue(int值){ this.value = value; } } 理论上我应该能够比较两个HasValue对象,如x.value> y.value。但是如果我输入 public class FastMaxHeap< T extends HasValue> { T [] data; int size; static final int HEAP_SIZE = 10000; @SuppressWarnings(unchecked) public FastMaxHeap(){ data =(T [])new Object [HEAP_SIZE]; size = 0; } } 现在我得到一个ClassCastException。这里发生了什么? Java泛型伤害了我的大脑。解决方案在第一种情况下 T extends Object 在运行时擦除为 Object 。在第二种情况下 T扩展了HasValue 被清除为 HasValue ,因此您需要拥有。 data =(T [])new HasValue [HEAP_SIZE]; 恕我直言,Java是不允许 new T [HEAP_SIZE ] 去做你必须做的事情。 I'm writing a simple implementation of a generic max heap. If I writepublic class FastMaxHeap<T>{ T[] data; int size; static final int HEAP_SIZE = 10000; @SuppressWarnings("unchecked") public FastMaxHeap(){ data = (T[]) new Object[HEAP_SIZE]; size = 0; }}it compiles. Now to actually implement the heap, i.e. write maxHeapify(), I need to be able to compare two T's. One option that a priori seems possible would be to tell the compiler that T implements Comparable. But if I type replace < T > with < T implements Comparable > the compiler complains -- how can I do this?Alternatively, I could define a class public class HasValue{ int value; public HasValue(int value){ this.value = value; }}and in theory I should then be able to compare two HasValue objects like x.value > y.value. But if I typepublic class FastMaxHeap<T extends HasValue>{ T[] data; int size; static final int HEAP_SIZE = 10000; @SuppressWarnings("unchecked") public FastMaxHeap(){ data = (T[]) new Object[HEAP_SIZE]; size = 0; }}I now get a ClassCastException. What is going on here? Java generics hurt my brain. 解决方案 In the first case T extends Object which is erased to Object at runtime.In the second case T extends HasValue is erased to HasValue so you need to have.data = (T[]) new HasValue[HEAP_SIZE];IMHO It is needlessly pedantic that Java doesn't allow new T[HEAP_SIZE] to do what you have to do anyway. 这篇关于通用类中的java通用转换的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持! 09-25 11:26