C和字符串

问题描述

我是c的新手，我遇到字符串有问题，任何人都可以给我一些

快速指针或指向好的c字符串教程？以下是我正在制作的

计划。


亲切的问候，

Anthony Irwin


#include< stdio.h>


char teststring [40] =" test string now";

char teststring1 [40] ;


int main（）{

printf（" teststring =％s"，teststring）;

strcpy（teststring1 ，teststring）;

printf（" \\\
teststring1 =％s"，teststring1）;


/ *如何为teststring分配新值说

*值我改变了字符串文本 * /


printf（" \ n\\\
II将teststring更改为=％s \ n"，teststring）;


返回0;

}

Hi,

I am new to c and am having trouble with strings can anyone give me some
quick pointers or point me to a good c strings tutorial? Below is a
program I am working on.

Kind Regards,
Anthony Irwin

#include <stdio.h>

char teststring[40] = "test string now";
char teststring1[40];

int main() {
printf("teststring = %s", teststring);
strcpy(teststring1, teststring);
printf("\nteststring1 = %s", teststring1);

/* How can I assign a new value to teststring say
* the value "I changed string text" */

printf("\n\nI changed teststring to = %s\n", teststring);

return 0;
}

推荐答案

strncpy（teststring，我更改了字符串文本，sizeof teststring-1）;


或


sprintf（teststring，"％。* s"，sizeof teststring-1，" I changed string

text"）;


转换说明符％。Ns表示不应写入不超过N

的字符;例如，我们可以写出

％。39s。使用*而不是常量意味着在

中指定了printf（）的一个参数（在本例中，通过表达式

sizeof teststring-1）。


表达式sizeof teststring-1给出了目的地的大小

缓冲区，少了0个终结符的一个字符，因此在这两种情况下，没有

将超过39个字符写入teststring。 />

strncpy(teststring, "I changed string text", sizeof teststring-1);

or

sprintf(teststring, "%.*s", sizeof teststring-1, "I changed string
text");

The conversion specifier "%.Ns" indicates that no more than N
characters should be written; for example, we could have written
"%.39s". Using * instead of a constant means that N is specified in
one of the arguments to printf() (in this case, by the expression
sizeof teststring-1).

The expression "sizeof teststring-1" gives the size of the destination
buffer, less one character for a 0 terminator, so in both cases, no
more than 39 characters are being written to teststring.

这篇关于C和字符串的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！