本文介绍了c++模板部分特化成员函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我是模板的新手,所以也许这是一件微不足道的事情,但我无法让它工作.我正在尝试获得类成员函数的部分专业化.最短的代码是:

I'm new to templates so maybe this is a trivial thing but I cannot get it to work. I'm trying to get partial specialization of a class member function. The shortest code would be:

template <typename T, int nValue> class Object{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; }
    Object& Deform(){
        m_t*=nValue;
        return *this;
    }
};

template <typename T>
Object<T,0>& Object<T,0>::Deform(){
    this->m_t = -1;
    return *this;
}

int main(){
    Object<int,7> nObj(1);
    nObj.Deform();
    std::cout<<nObj.Get();
}

我尝试过非成员函数,效果很好.成员函数的完全特化也能正常工作.

I tried with nonmember functions and that's worked fine. What also works fine is full specialization of a member function.

但是,每当我尝试使用部分规范时.的成员函数我得到形式的错误:

But, whenever I try with partial spec. of a member function I get error of the form:

PartialSpecification_MemberFu.cpp(17): error: template argument
list must match the parameter list Object<T,0>& Object<T,0>::Deform().

希望得到任何帮助:-)

Would appreciate any help :-)

推荐答案

你不能部分特化一个成员函数,你必须部分特化整个类.因此你需要类似的东西:

You cannot partially specialize only a single member function, you must partially specialize the whole class. Hence you'll need something like:

template <typename T>
class Object<T, 0>
{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; }
    Object& Deform()
    {
        std::cout << "Spec
";
        m_t = -1;
        return *this;
    }
};

这篇关于c++模板部分特化成员函数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

05-27 15:53