为什么在C ++ 0x中没有编译器生成的swap（）方法？

问题描述

C ++编译器自动生成复制构造函数和复制赋值运算符。为什么不 swap 也？

C++ compilers automatically generate copy constructors and copy-assignment operators. Why not swap too?

这些天，实现复制赋值运算符的首选方法是复制-swap idiom：

These days the preferred method for implementing the copy-assignment operator is the copy-and-swap idiom:

T& operator=(const T& other)
{
    T copy(other);
    swap(copy);
    return *this;
}

（ 。根据（我不知道如何读得很好），它是回迁。它在标题为未准备好C ++ 0x，但打开以后将重新提交的部分列出。所以看起来像它不会是C ++ 0x的一部分，但可能稍后添加。

I did a bit of searching, and the proposal for = default move was proposal n2583. According to this (which I don't know how to read very well), it was "moved back." It is listed under the section titled "Not ready for C++0x, but open to resubmit in future ". So looks like it won't be part of C++0x, but may be added later.

有点失望。 ：（

编辑2：再看一下，我发现这个：这是更新的，看起来像我们可以默认 move 。Yay！

EDIT 2: Looking around a bit more, I found this: Defining Move Special Member Functions which is much more recent, and does look like we can default move. Yay!

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