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问题描述
这个语句是真的吗
任何人都可以站点一个例子..或提供一些链接...
解决方案
是的,你可以这样做,你可以像c这样的过程语言模拟继承和多态性之类的OOP概念。
由于你要求一个代码示例,这里是一个:
要模拟继承,你需要的是结构的第一个成员是
struct BaseClass
{
// ...
};
struct DerivedClass
{
struct BaseClass super;
// ....
};
struct DerivedClass d;
// UpCasting示例
struct BaseClass * base_ptr =(struct BaseClass *)& d;
//下载示例
struct DerivedClass * derived_ptr =(struct DerivedClass *)base_ptr;
当然,如果你真的需要OOP,你应该使用OOP语言,而不是这样。 / p>
Is this statement true??
Can anybody site an example.. or provide some links...
解决方案
Yes, you can do that, You can simulate OOP concepts like Inheritance and Polymorphism in a procedural language like c.
Since you ask for a Code Example, Here is one:
To simulate Inheritance all you need is the first member of a structure be an instance of the superclass, and then you can cast around pointers to base and derived classes just like C++ inheritance.
struct BaseClass
{
//...
};
struct DerivedClass
{
struct BaseClass super;
//....
};
struct DerivedClass d;
//UpCasting example
struct BaseClass *base_ptr = (struct BaseClass *)&d;
//Downclasting Example
struct DerivedClass *derived_ptr = (struct DerivedClass *)base_ptr;
Ofcourse, If you really need OOP you should use a OOP language rather than playing around this way.
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