问题描述
大家好.我正在为自己的工作修复旧代码.它目前是用C ++编写的.他们将静态分配转换为动态分配，但未编辑memsets/memcmp/memcpy.这是我第一次编程实习，所以对我的新手式问题不屑一顾.
Hey guys. I am working on fixing older code for my job. It is currently written in C++. They converted static allocation to dynamic but didn't edit the memsets/memcmp/memcpy. This is my first programming internship so bare with my newbe-like question.
以下代码在C中，但是我想在C ++中使用(我读到malloc在C ++中不是一种好习惯).我有两种情况:首先，我们创建了f.然后，您可以使用& f来填充零.第二个是指针* pf.我不确定如何将pf设置为全0，就像C ++中的上一个示例一样.
The following code is in C, but I want to have it in C++ ( I read that malloc isn't good practice in C++). I have two scenarios: First, we have f created. Then you use &f in order to fill with zero. The second is a pointer *pf. I'm not sure how to set pf to all 0's like the previous example in C++.
您可以只执行pf = new foo而不是malloc然后调用memset(pf, 0, sizeof(foo))吗?
Could you just do pf = new foo instead of malloc and then call memset(pf, 0, sizeof(foo))?
struct foo { ... } f;
memset( &f, 0, sizeof(f) );
//or
struct foo { ... } *pf;
pf = (struct foo*) malloc( sizeof(*pf) );
memset( pf, 0, sizeof(*pf) );
推荐答案
是的，但前提是foo是POD.如果它具有虚拟函数或远程C ++ ish以外的任何其他功能，请不要在其上使用memset，因为它会遍历struct/class的内部.
Yes, but only if foo is a POD. If it's got virtual functions or anything else remotely C++ish, don't use memset on it since it'll stomp all over the internals of the struct/class.
您可能想代替memset做的是给foo一个构造函数，以显式初始化其成员.
What you probably want to do instead of memset is give foo a constructor to explicitly initialise its members.
如果要使用new，请不要忘记相应的删除.更好的方法是使用shared_ptr:)
If you want to use new, don't forget the corresponding delete. Even better would be to use shared_ptr :)
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