问题描述
我想以此为榜样的但我不断收到错误。下面的例子中，我得到一个错误试图访问一个私有变量（不够公平）：
I'm trying to follow this example http://www.boost.org/doc/libs/1_42_0/libs/serialization/doc/serialization.html#constructors but I keep getting errors. Following the example, I get an error trying to access a private variable (fair enough):
bs.cpp:10: error: ‘const int my_class::m_attribute’ is private
但是，如果我添加save_construct_data作为一个朋友，我得到一个模糊的错误：
But, if I add save_construct_data as a friend, I get an ambiguity error:
/usr/include/boost/serialization/serialization.hpp:148: error: call of overloaded ‘save_construct_data(boost::archive::text_oarchive&, const my_class*&, const boost::serialization::version_type&)’ is ambiguous
/usr/include/boost/serialization/serialization.hpp:83: note: candidates are: void boost::serialization::save_construct_data(Archive&, const T*, unsigned int) [with Archive = boost::archive::text_oarchive, T = my_class]
bs.cpp:10: note: void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
bs.cpp:29: note: void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
我可以将函数定义为友元声明，但那只是丑陋的。
I can move the function definition to the friend declaration, but that's just ugly.
我应该尝试下？
谢谢，
Jayen
Thanks,Jayen
推荐答案
save_construct_data已被宣布它可以添加为朋友之前。一些关于在不同的命名空间中。像这样的：
save_construct_data has to be declared before it can be friended. Something about being in a different namespace. Like this:
namespace boost { namespace serialization {
template<class Archive>
inline void save_construct_data(Archive & ar, const my_class * t, const unsigned int file_version);
}}
不过，因为这取决于my_class，您必须声明my_class还有：
But, because that depends on my_class, you have to declare my_class as well:
class my_class;
所以整个事情看起来像<一个href=\"http://pastebin.com/embed_iframe.php?i=aFyCpjyY\">http://pastebin.com/embed_iframe.php?i=aFyCpjyY
这篇关于序列化指针类时没有默认构造函数的麻烦覆盖save_construct_data的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！