本文介绍了等待在F#的IAsyncOperation的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在F#以下code:

I have the following code in F#:

   let CreateSampleDataFromJson<'T>(path) =
      let uri = new Uri(path)
      async {
         let file = StorageFile.GetFileFromApplicationUriAsync(uri)
         let jsonText = FileIO.ReadTextAsync(file)
         return JsonObject<'T>.Parse(jsonText)
      }

我遇到的问题是,文件 IAsyncOperation&LT; StorageFile&GT; ,而不是 StorageFile ReadTextAsync 预计。

在C#中,你可以做一些类似的:

In C# you can do something similar to this:

var file = await StorageFile.GetFileFromApplicationUriAsync(uri)

public async Task<T> CreateSampleDataFromUrl<T>(string path)
{
  var uri = new Uri(path);
  var file = await StorageFile.GetFileFromApplicationUriAsync(uri);
  var jsonText = await FileIO.ReadTextAsync(file);
  return JsonObject<T>.Parse(jsonText);
}

问题是,我不知道如何等待一个 IAsyncOperation F#中。通常让!不起作用。即以下编译失败:

The problem is that I don't know how to await an IAsyncOperation in F#. The usual let! doesn't work. i.e. the following fails to compile:

async {
   let! file = StorageFile.GetFileFromApplicationUriAsync(uri)

通过编译器错误:

error FS0001: This expression was expected to have type    Async<'a>    but here has type    IAsyncOperation<StorageFile>

我发现了一份文件,称有一个在 System.WindowsRuntimeSystemExtensions 类中定义的 AsTask()扩展方法,我可以使用如下:

I found a document that said there's an AsTask() extension method defined in the System.WindowsRuntimeSystemExtensions class which I can use as follows:

 let! file = StorageFile.GetFileFromApplicationUriAsync(uri).AsTask() |> Async.AwaitTask

有没有使这是一个更好一点的地方这样做,或可用的东西在F#库的标准方式?

Is there a standard way of doing this or something available in an F# library somewhere that makes this a bit nicer?

推荐答案

您的解决方案由我似乎罚款。如果你正在寻找一个更好的语法,如何滚动它变成这样的功能(没有可能无偿类型注释):

Your solution seems fine by me. If you're looking for a nicer syntax, how about rolling it into a function like this (without the possibly gratuitous type annotations):

let await<'a> (op: IAsyncOperation<'a>) : Async<'a> =
   op.AsTask() |> Async.AwaitTask

这会给你你会在C#中看到几乎相同的语法:

This will give you the almost exact same syntax you'd see in c#:

async {
   let! file = await <| StorageFile.GetFileFromApplicationUriAsync(uri)
   ...
}

您与您的previous方法被越来越编译器错误是可以预期的。所有异步工作流程在乎的是F#异步特异型。这种类型给你一个的方式与.NET世界中通过任务其余的互操作,但仅此而已。 IAsyncOperation是从'世界不同部分',我不希望F#核心库很快支持。

The compiler errors you were getting with your previous approaches are to be expected. All async workflow cares about is the F#-specific Async type. This type gives you a way to interop with the rest of .NET world through Tasks, but that's it. IAsyncOperation is from a 'different part of the world', I wouldn't expect F# core libraries to support it anytime soon.

这篇关于等待在F#的IAsyncOperation的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

05-27 09:55