关于在基类和派生类中实现接口的问题

问题描述

我得到了游泳，嘎嘎和苍蝇的输出。我不知道如何从派生类Mallard，RubberDuck和DecoyDuck获取输出。从基类实现派生类时，我做错了吗？任何人都可以帮助我。

I am getting output as swim, quack and fly. I don't know how to get output from my derived class Mallard, RubberDuck and DecoyDuck. Am I doing anything wrong while implementing derived class from my base class? Can anyone help me.

{
    interface IFlyBehavior
    {
        void Action1();
    }
    interface IQuackBehavior:IFlyBehavior
    {
        void Action2();
    }
    interface ISwimBehavior:IQuackBehavior
    {
        void Action3();
    }
    public class Duck:IQuackBehavior
    {
        public void Action1()
        {
           Console.WriteLine("fly");
        }
        public void Action2()
        {
            Console.WriteLine("quack");
        }
        public void Action3()
        {
            Console.WriteLine("Swim");
        }
    }
    public class Mallard: Duck, IFlyBehavior, IQuackBehavior, ISwimBehavior
    {
       public void Action1(string fly, string quack, string swim){
        Console.WriteLine("This duck can {0}, {1}, and {2}", fly, quack, swim);}
    }
    public class RubberDuck: Duck, IFlyBehavior, IQuackBehavior, ISwimBehavior
    {
         public void Action2(string fly, string quack, string swim)
         {
       Console.WriteLine ("This is rubberduck so it might float on water but cannot {0}, {1} or {2}",fly,quack,swim);
       }
    }
    public class DecoyDuck: Duck, IFlyBehavior, IQuackBehavior, ISwimBehavior
    {
         public void Action3(string fly, string swim, string quack) {
        Console.WriteLine("This duck cannot {0}, but {1}, and may be able to {2}",fly,swim,quack);}
    }
    class Program
    {
        static void Main()
        {
            Duck M = new Mallard();
            Duck R = new RubberDuck();
            Duck D = new DecoyDuck();
            M.Action1();
            R.Action2();
            D.Action3();


        }
    }
}

推荐答案

这篇关于关于在基类和派生类中实现接口的问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！