本文介绍了如何使用ARCore测量距离?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

限时删除!!

是否可以计算两个HitResult`s之间的距离?

Is it possible to calculate distance between two HitResult `s ?

或者我们如何使用ARCore计算真实距离(例如米)?

Or how we can calculate real distance (e.g. meters) using ARCore?

推荐答案

在Java ARCore中,世界单位是米(我刚刚意识到我们可能不会对此进行记录... aaa看起来不行.糟糕,错误归档).通过减去两个Pose的平移分量,您可以获得它们之间的距离.您的代码如下所示:

In Java ARCore world units are meters (I just realized we might not document this... aaaand looks like nope. Oops, bug filed). By subtracting the translation component of two Poses you can get the distance between them. Your code would look something like this:

首次命中为hitResult:

startAnchor = session.addAnchor(hitResult.getHitPose());

第二次命中为hitResult:

Pose startPose = startAnchor.getPose();
Pose endPose = hitResult.getHitPose();

// Clean up the anchor
session.removeAnchors(Collections.singleton(startAnchor));
startAnchor = null;

// Compute the difference vector between the two hit locations.
float dx = startPose.tx() - endPose.tx();
float dy = startPose.ty() - endPose.ty();
float dz = startPose.tz() - endPose.tz();

// Compute the straight-line distance.
float distanceMeters = (float) Math.sqrt(dx*dx + dy*dy + dz*dz);

假定这些命中结果不在同一帧上发生,则创建Anchor很重要,因为每次调用Session.update()时都可以重塑虚拟世界.通过使用锚点而不是仅使用Pose保持该位置,其Pose将会更新以在这些重塑过程中跟踪物理特征.

Assuming that these hit results don't happen on the same frame, creating an Anchor is important because the virtual world can be reshaped every time you call Session.update(). By holding that location with an anchor instead of just a Pose, its Pose will update to track the physical feature across those reshapings.

这篇关于如何使用ARCore测量距离?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

1403页,肝出来的..

09-06 06:56