在歧视表中

问题描述

如何从一个特定作者中选择所有项目？可能这样吗？或者如果我想要许多项目类型和项目包（项目有很多项目），我如何编辑实体？

How can I select all items from one specific author ? Its possible this way ? Or how can I edit entities if I want many item types and item packages (item has many items) too ?

项目

/**
 * @ORM\Table()
 * @ORM\Entity
 * @ORM\InheritanceType("JOINED")
 * @ORM\DiscriminatorColumn(name="discr", type="string")
 * @ORM\DiscriminatorMap({
 * "cd"   = "ItemCD",
 * "dvd"   = "ItemDVD",
 * "pack" = "ItemPack",
 * })
 */
class Item
{

    /**
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     */
    private $id;

    /**
     * @ORM\Column(name="name", type="string", length=250, nullable=false)
     */
    private $name;

}

ItemCD

/**
 * @ORM\Table()
 * @ORM\Entity
 */
class ItemCD extends Item
{

    /**
     * @ORM\ManyToOne(targetEntity="Author", inversedBy="item")
     * @ORM\JoinColumn(name="author_id", referencedColumnName="id")
     */
    private $author;

}

ItemDVD

/**
 * @ORM\Table()
 * @ORM\Entity
 */
class ItemDVD extends Item
{

    /**
     * @ORM\ManyToOne(targetEntity="Author", inversedBy="item")
     * @ORM\JoinColumn(name="author_id", referencedColumnName="id")
     */
    private $author;

}

ItemPack

/**
 * @ORM\Table()
 * @ORM\Entity
 */
class ItemPack extends Item
{

    /**
     * @ORM\ManyToMany(targetEntity="Item", inversedBy="item")
     * @ORM\JoinTable()
     */
    private $items;

}

作者

/**
 * @ORM\Table()
 * @ORM\Entity
 */
class Author
{

    /**
     * @ORM\Column(name="id", type="integer", nullable=false)
     * @ORM\Id
     * @ORM\GeneratedValue(strategy="IDENTITY")
     *
     */
    private $id;

    /**
     * @ORM\Column(name="name", type="string", length=250, nullable=false)
     */
    private $name;

}

推荐答案

必须查询特定元素。这是一个已知的（和想要的）限制，因为DQL是一种静态类型的语言：参见

You will have to query for specific elements. This is a known (and wanted) limitation, since DQL is a static typed language: see http://www.doctrine-project.org/jira/browse/DDC-16

相关：

使用解决方法处理此问题的方法是在DQL中使用2个子查询：

A way of handling this with a workaround is using 2 subqueries in your DQL:

SELECT
    i
FROM
    Item i
WHERE
    i.id IN(
        SELECT 
            i2.id
        FROM
            ItemDvd i2
        WHERE
            i2.author = :author
    )
    OR
    i.id IN(
        SELECT
            i3.id
        FROM
            ItemCd i3
        WHERE
            i3.author = :author
    )

您可以看到，您必须手动提取每个可能的子类型的标识符。

As you can see you have to extract the identifiers for each possible subtype manually.

编辑：从给定的作者获取所有包连同单个DVD或CD），查询变得更糟：

to get all the packs from a given author (along with single DVDs or CDs), the query becomes even worse:

SELECT
    i
FROM
    Item i
WHERE
    i.id IN(
        SELECT 
            i2.id
        FROM
            ItemDvd i2
        WHERE
            i2.author = :author
    )
    OR
    i.id IN(
        SELECT
            i3.id
        FROM
            ItemCd i3
        WHERE
            i3.author = :author
    )
    OR
    i.id IN(
        SELECT
            i4.id
        FROM
            ItemPack i4
        JOIN
            i4.items i5
        WHERE
            i5.id IN (
                SELECT
                    i6.id
                FROM
                    Item i6
                WHERE
                    i6.id IN(
                        SELECT 
                            i7.id
                        FROM
                            ItemDvd i7
                        WHERE
                            i7.author = :author
                    )
                    OR
                    i6.id IN(
                        SELECT
                            i8.id
                        FROM
                            ItemCd i8
                        WHERE
                            i8.author = :author
                    )
            )
    )

这篇关于在歧视表中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！