交换元件结构的数组

问题描述

说我有这样的结构：

struct MyStruct {
  int iID;
  int iMyNumber;
};

然后我定义MyStructs数组：

Then I define an array of MyStructs:

struct MyStruct msTest[3];

我通过查看标识上做一个结构类似这样的排序操作。现在，只要我找出哪些记录应交换到数组排序我必须做实际的交换。我想这样的：

I'm doing a sorting operation on a struct similar to this one by looking at the ID. Now, as soon as I find out which records should be swapped to sort the array I have to do the actual swapping. I tried this:

if (iSmallest != iCntr) {
    stPTmp = &stXDB[iCntr];
    &stXDB[iCntr] = &stXDB[iSmallest];
    &stXDB[iSmallest] = &stPTmp;
}

stPTmp被定义为无效* stPTmp; 和 iCntr 和 iSmallest 包含记录的索引来进行交换。我的code不工作，但我怎么解决？

stPTmp is defined as void *stPTmp; and iCntr and iSmallest contain the indices of the records to be swapped. My code doesn't work, but how do I fix it?

推荐答案

您需要交换的元素，不是指针，

You need to swap elements, not pointers,

struct MyStruct stTmp;

if (iSmallest != iCntr) {
    stTmp = stXDB[iCntr];
    stXDB[iCntr] = stXDB[iSmallest];
    stXDB[iSmallest] = stTmp;
}

不是特别有效，但你的结构是小，所以它只有一点点比交换指针更贵。

Not terribly efficient, but your structs are small, so its only a bit more expensive than swapping pointers.

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