字节数组到PHP中的UTF-8字符串?

问题描述

如何将字节数组转换为UTF-8字符串?我需要这个，因为我是从二进制格式中提取的.

How can I convert an array of bytes into a UTF-8 string? I need this because I am extracting from a binary format.

推荐答案

字符串不过是字节数组.因此，UTF-8字符串与字节数组非常相似，不同之处在于您还知道字节数组代表什么.

A string is nothing more than an array of bytes. So a UTF-8 string is the very same as an array of bytes, except that in addition you know what the array of bytes represent.

因此，您输入的字节数组还需要其他信息:字符集(字符编码).如果您知道输入字符集，则可以将字节数组转换为代表UTF-8字符串的另一个字节数组.

So your input array of bytes needs one more additional information as well: the character set (character encoding). If you know the input character set, you can convert the array of bytes to another array of bytes representing an UTF-8 string.

用于执行此操作的PHP方法称为 mb_convert_encoding() .

The PHP method for doing that is called mb_convert_encoding().

PHP本身不知道字符集(字符编码).因此，字符串实际上无非就是字节数组.该应用程序必须知道如何处理.

PHP itself does not know of character sets (character encodings). So a string really is nothing more than an array of bytes. The application has to know how to handle that.

因此，如果您有一个字节数组，并且想将其转换为PHP字符串，以便使用mb_convert_encoding()转换字符集，请尝试以下操作:

So if you have an array of bytes and want to turn that into a PHP string in order to convert the character set using mb_convert_encoding(), try the following:

$input = array(0x53, 0x68, 0x69);
$output = '';
for ($i = 0, $j = count($input); $i < $j; ++$i) {
    $output .= chr($input[$i]);
}
$output_utf8 = mb_convert_encoding($output, 'utf-8', 'enter input encoding here');

(而不是上面的单个示例，请在 https://stackoverflow.com/a/5473057/上查看更多示例530502 .)

(Instead of the single example above, have a look at more examples at https://stackoverflow.com/a/5473057/530502.)

$output_utf8将是输入字节数组的PHP字符串，该字节数组转换为UTF-8.

$output_utf8 then will be a PHP string of the input array of bytes converted to UTF-8.

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