本文介绍了如何解析使用的JSONObject这种反应的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有这样的反应,我回去形式的服务器。我想分析它,并获得hospital_name出来。我会怎么做呢?

  [
    {
        医院:{
            ID:63083,
            hospital_name:科罗拉多州精神健康研究所,
            hospital_add_1:1600W,24日ST,
            hospital_add_2:空,
            hospital_city:普韦布洛号,
            hospital_state:CO,
            hospital_zip:81003,
            hospital_phone:719-546-4000 \\ R,
            hospital_fax:空,
            hospital_description:空,
            callcenter_agent_approval:0,
            hospital_site:,
            mdpocket_approval:0,
            脸谱:
        },
        楼:[],
        部: [],
        图片: [],
        注意事项:[]
    },
    {
        医院:{
            ID:63084,
            hospital_name:阳明山庄医学中心,
            hospital_add_1:400瓦16街
            hospital_add_2:空,
            hospital_city:普韦布洛号,
            hospital_state:CO,
            hospital_zip:81003,
            hospital_phone:719-584-4000 \\ R,
            hospital_fax:空,
            hospital_description:空,
            callcenter_agent_approval:0,
            hospital_site:,
            mdpocket_approval:0,
            脸谱:
        },
        楼:[],
        部: [],
        图片: [],
        注意事项:[]
    },
    {
        医院:{
            ID:63085,
            hospital_name:圣玛丽 - 考文医学中心,
            hospital_add_1:1008 Minnequa大道
            hospital_add_2:空,
            hospital_city:普韦布洛号,
            hospital_state:CO,
            hospital_zip:81004,
            hospital_phone:719-560-4000 \\ R,
            hospital_fax:空,
            hospital_description:空,
            callcenter_agent_approval:0,
            hospital_site:,
            mdpocket_approval:0,
            脸谱:
        },
        楼:[],
        部: [],
        图片: [],
        注意事项:[]
    }
]

编辑的JSON
*的已更新JSON *


解决方案

  [// JSON数组节点
{// JSON对象节点
医院:{// json对象医院

要解析

  JSONArray JR =新JSONArray(jsonstring);
的for(int i = 0; I< jr.length();我++)
{
   JB的JSONObject =(JSONObject的)jr.getJSONObject(I)
   JSONObject的JB1 =(JSONObject的)jb.getJSONObject(医院);
   字符串名称= jb1.getString(hospital_name);
   Log.i(名......,名);
}

登录

  3月2日至十八日:09:43.950:I /名称....(951):科罗拉多州精神健康研究所
3月二日至18日:09:43.950:I /名称....(951):阳明山庄医疗中心
3月二日至18日:09:43.950:I /名称....(951):圣玛丽 - 考文医学中心

I have this response that I get back form server. I want to parse it and get the hospital_name out of it. How would I go about it?

[
    {
        "Hospital": {
            "id": "63083",
            "hospital_name": "Colorado Mental Health Inst",
            "hospital_add_1": "1600 W 24th St",
            "hospital_add_2": null,
            "hospital_city": "Pueblo",
            "hospital_state": "CO",
            "hospital_zip": "81003",
            "hospital_phone": "719-546-4000\r",
            "hospital_fax": null,
            "hospital_description": null,
            "callcenter_agent_approval": "0",
            "hospital_site": "",
            "mdpocket_approval": "0",
            "facebook": ""
        },
        "Floor": [],
        "Department": [],
        "Image": [],
        "Notes": []
    },
    {
        "Hospital": {
            "id": "63084",
            "hospital_name": "Parkview Medical Center",
            "hospital_add_1": "400 W 16th St",
            "hospital_add_2": null,
            "hospital_city": "Pueblo",
            "hospital_state": "CO",
            "hospital_zip": "81003",
            "hospital_phone": "719-584-4000\r",
            "hospital_fax": null,
            "hospital_description": null,
            "callcenter_agent_approval": "0",
            "hospital_site": "",
            "mdpocket_approval": "0",
            "facebook": ""
        },
        "Floor": [],
        "Department": [],
        "Image": [],
        "Notes": []
    },
    {
        "Hospital": {
            "id": "63085",
            "hospital_name": "St Mary-Corwin Medical Center",
            "hospital_add_1": "1008 Minnequa Ave",
            "hospital_add_2": null,
            "hospital_city": "Pueblo",
            "hospital_state": "CO",
            "hospital_zip": "81004",
            "hospital_phone": "719-560-4000\r",
            "hospital_fax": null,
            "hospital_description": null,
            "callcenter_agent_approval": "0",
            "hospital_site": "",
            "mdpocket_approval": "0",
            "facebook": ""
        },
        "Floor": [],
        "Department": [],
        "Image": [],
        "Notes": []
    }
]

EDITED THE JSON*UPDATED JSON *

解决方案
[ // json array node 
{  // json object node 
"Hospital": { // json object Hospital 

To parse

JSONArray jr = new JSONArray("jsonstring");
for(int i=0;i<jr.length();i++)
{
   JSONObject jb = (JSONObject)jr.getJSONObject(i);
   JSONObject jb1 =(JSONObject) jb.getJSONObject("Hospital");
   String name =  jb1.getString("hospital_name");
   Log.i("name....",name);
}

Log

02-18 03:09:43.950: I/name....(951): Colorado Mental Health Inst
02-18 03:09:43.950: I/name....(951): Parkview Medical Center
02-18 03:09:43.950: I/name....(951): St Mary-Corwin Medical Center

这篇关于如何解析使用的JSONObject这种反应的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!

09-16 02:31