如何在Java中生成所有可能的64位随机值?

问题描述

考虑到Java SecureRandom.nextLong()是否从仅使用48位的 Random 继承，它是否返回所有可能的值?如果没有，我是否仍可以通过修改Random类以及如何做到这一点在Java中完成呢?我只想使用一个全随机的长数生成器，如果可能的话，可以返回所有可能的长值.

Does Java SecureRandom.nextLong() return all possible values given it inherits from Random which uses only 48 bits? If not, can I still do it in Java maybe by modifying the Random class and how to do it? I just want to use an all random long number generator where all possible long values can be returned, if possible.

推荐答案

尽管SecureRandom继承自Random，但它使用的数学方式不同或具有相同的限制.最终将产生所有可能的64位值.

While SecureRandom inherits from Random, it doesn't use the same maths or have the same limitation. It will produce all possible 64-bit values eventually.

该类委托许多可能的实现之一.您可以通过调用 SecureRandom.getInstance(algorithm)

This class delegates to one of many possible implementations. You can select one by calling SecureRandom.getInstance(algorithm)

注意:某些实现使用计算机中的熵使结果随机，而不是纯伪随机.

Note: some implementations use entropy in your computer to make the results random, rather than purely pseudo random.

SecureRandom不使用其父级的任何方法，例如

SecureRandom doesn't use any of the methods of it's parent e.g.

/**
 * The provider implementation.
 */
private SecureRandomSpi secureRandomSpi = null;

public void nextBytes(byte[] bytes) {
    secureRandomSpi.engineNextBytes(bytes);
}

此方法委托一个完全不同的实现.

This method delegates to a completely different implementation.

相关链接如何解决缓慢的Java"SecureRandom"问题?使用/dev/random

Related link How to solve slow Java `SecureRandom`? due to using /dev/random

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