问题描述
我有一个 luigi python 任务,其中包括一些 pyspark 库.现在我想用 spark-submit 在 mesos 上提交这个任务.我应该怎么做才能运行它?下面是我的代码框架:
I have a luigi python task which includes some pyspark libs. Now I would like to submit this task on mesos with spark-submit. What should I do to run it? Below is my code skeleton:
from pyspark.sql import functions as F
from pyspark import SparkContext
class myClass(SparkSubmitTask):
# date = luigi.DateParameter()
def __init__(self, date):
self.date = date # date is datetime.date.today().isoformat()
def output(self):
def input(self):
def run(self):
# Some functions are using pyspark libs
if __name__ == "__main__":
luigi.run()
没有 luigi,我将此任务作为以下命令行提交:
Without luigi, I'm submmitting this task as the following command-line:
/opt/spark/bin/spark-submit --master mesos://host:port --deploy-mode cluster --total-executor-cores 1 --driver-cores 1 --executor-memory 1G --driver-memory 1G my_module.py
现在的问题是如何触发提交包含 luigi 命令行的 luigi 任务,例如:
Now the problem is how I can spark-submit the luigi task that includes luigi command-line such as:
luigi --module my_module myClass --local-scheduler --date 2016-01
还有一个问题是如果 my_module.py 有一个需要先完成的任务,我需要为它做更多的事情还是只是设置与当前命令行相同?
One more question is if my_module.py has a required task to finish first, do I need to do something more for it or just set the same as the current command-line?
我非常感谢您对此的任何提示或建议.非常感谢.
I really appreciate for any hints or suggestions for this. Thanks very much.
推荐答案
Luigi 有一些模板任务.其中之一称为 PySparkTask.您可以从此类继承并覆盖属性:
Luigi has some template Tasks. One of them called PySparkTask.You can inherit from this class and override the properties:
https://github.com/spotify/luigi/blob/master/luigi/contrib/spark.py.
我还没有测试过,但根据我对 luigi 的经验,我会尝试这个:
I haven't tested it but based on my experience with luigi I would have try this:
import my_module
class MyPySparkTask(PySparkTask):
date = luigi.DateParameter()
@property
def name(self):
return self.__class__.__name__
@property
def master(self):
return 'mesos://host:port'
@property
def deploy_mode(self):
return 'cluster'
@property
def total_executor_cores(self):
return 1
@property
def driver_cores(self):
return 1
@property
def executor-memory(self):
return 1G
@property
def driver-memory(self):
return 1G
def main(self, sc, *args):
my_module.run(sc)
def self.app_options():
return [date]
然后你可以运行它:luigi --module task_module MyPySparkTask --local-scheduler --date 2016-01
Then you can run it with: luigi --module task_module MyPySparkTask --local-scheduler --date 2016-01
还有一个选项可以在 client.cfg 文件中设置属性,以使它们成为其他 PySparkTasks 的默认值:
There is also an option to set the properties in a client.cfg file in order to make them the default values for other PySparkTasks:
[spark]
master: mesos://host:port
deploy_mode: cluster
total_executor_cores: 1
driver_cores: 1
executor-memory: 1G
driver-memory: 1G
这篇关于如何使用 spark-submit 和 pyspark 运行 luigi 任务的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!