使用slim或haml在独立(非Rails)ruby应用程序中指定布局和模板

问题描述

我正在尝试在独立的应用程序(而不是Rails)中执行以下操作:

I'm trying to do something like this in a standalone (not rails) app:

layout.slim:

layout.slim:

h1 Hello
.content
  = yield

show.slim:

show.slim:

= object.name
= object.description

我不知道如何指定布局和模板.苗条(或haml)有可能吗?谢谢.

I can't figure out how to specify a layout and a template. Is this possible with slim (or haml)? Thanks.

推荐答案

layout.slim文件如下:

The layout.slim file looks like:

h1 Hello
.content
  == yield

contents.slim文件如下:

The contents.slim file looks like:

= name

这可以缩短，但出于解释目的，我将其分为几个步骤.

This can be shortened, but I separated to individual steps for explanation purposes.

require 'slim'

# Simple class to represent an environment
class Env
  attr_accessor :name
end

# Intialize it
env = Env.new
# Set the variable we reference in contents.slim
env.name = "test this layout"

# Read the layout file in as a string
layout = File.open("layout.slim", "rb").read

# Read the contents file in as a string
contents = File.open("contents.slim", "rb").read

# Create new template object with the layout
l = Slim::Template.new { layout }

# Render the contents passing in the environment: env
# so that it can resolve: = name
c = Slim::Template.new { contents }.render(env)

# Render the layout passing it the rendered contents
# as the block. This is what yield in layout.slim will get
puts l.render{ c }

这将输出:

<h1>Hello</h1><div class="content">test this layout</div>

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