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问题描述

有没有类似在C#中的东西的sprintf()



我想比如说想转换一个整型到2字节的字节数组



是这样的:

  INT数= 17; 
字节[] S = sprintf的(%2C号);


解决方案

原来,这是我真正想要的是这个

 短号码= 17; 
System.IO.BinaryWriter作家=新System.IO.BinaryWriter(流);
writer.Write(数);
writer.Flush();



这里的关键是类的BinaryWriter的写入功能。它有18个重载,转换成不同的格式为一个字节数组,它写入流。在我来说,我必须确保我想写保持在很短的数据类型的数量,这将使Write函数写入2个字节。


Is there something similar to sprintf() in C#?

I would for instance like to convert an integer to a 2-byte byte-array.

Something like:

int number = 17;
byte[] s = sprintf("%2c", number);
解决方案

It turned out, that what I really wanted was this:

short number = 17;
System.IO.BinaryWriter writer = new System.IO.BinaryWriter(stream);
writer.Write(number);
writer.Flush();

The key here is the Write-function of the BinaryWriter class. It has 18 overloads, converting different formats to a byte array which it writes to the stream. In my case I have to make sure the number I want to write is kept in a short datatype, this will make the Write function write 2 bytes.

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10-28 16:13