如何判断给定参数是否为C ++ 03中的右值？我写了一些非常通用的代码，如果可能的话需要参考，否则构造一个新的对象。我可以重载以取值以及by-reference和rvalue返回调用by-value函数？
或者我有一个非常恶心的感觉这是为什么右值引用是在C ++ 0x？
编辑：
is_rvalue =！显然有一种方法可以确定一个表达式是否为C ++ 03中的右值或左值（如果是这样的话）：
注意这篇文章是相当沉重的阅读（至少是对我来说）;正如Neibler所说：
使用artcile中描述的rvalue检测可能会帮助您处理任何表达式的至少一些C ++ 0x的右值引用解析的问题。
How can you tell whether or not a given parameter is an rvalue in C++03? I'm writing some very generic code and am in need of taking a reference if possible, or constructing a new object otherwise. Can I overload to take by-value as well as by-reference and have the rvalue returns call the by-value function?
Or do I have a very sickening feeling that this is why rvalue references are in C++0x?
Edit:
is_rvalue = !(is_reference || is_pointer) ?
There apparently is a way to determine whether an expression is an rvalue or lvalue in C++03 (I say apparently because I'm not sure how well I understand the technique). Note that to make the technique usable, preprocessor macros are pretty much required. Eric Niebler has written a nice article about how it works and how it gets used in BOOST_FOREACH:
Note that the article is pretty heavy reading (at least it is for me); as Neibler says in it:
Using the rvalue detection described in the artcile might help you deal with at least some of the issues that C++0x's rvalue references solve.
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