如何删除具有特定列号和行号的所有值?

问题描述

此代码花费的时间太长:

This code takes too long time:

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
for(int i = firstIndex-1; i < lastIndex; i++) {
    try {
        DataLogg dataLogg = selectedLogger.get(i);
        if (dataLogg != null) {
            dataLoggRepository.delete(dataLogg);
        }
    } catch(Exception e1) {}
}

有什么办法可以避免此for循环，并且仍然删除列值loggerId.getValue()的firstIndex-1和lastIndex之间的所有内容?

Is there any way I can avoid this for-loop, and still delete everything between firstIndex-1 and lastIndex that have the column value loggerId.getValue()?

来自以下评论的建议:

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
List<DataLogg> deleteThese = new ArrayList<DataLogg>();
for(int i = firstIndex-1; i < lastIndex; i++) {
    try {
        DataLogg dataLogg = selectedLogger.get(i);
        deleteThese.add(dataLogg);
    } catch(Exception e1) {}
}
dataLoggRepository.deleteInBatch(deleteThese);

推荐答案

另一种编写方式.

List<DataLogg> selectedLogger = dataLoggRepository.findByLoggerId(loggerId.getValue());
List<DataLogg> deleteThese = IntStream.range(firstIndex - 1, lastIndex).mapToObj(i -> selectedLogger.get(i)).collect(Collectors.toList());
dataLoggRepository.deleteInBatch(deleteThese);

这篇关于如何删除具有特定列号和行号的所有值?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！