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问题描述

我正在尝试使用一个队列数组创建一个 priority队列,该数组的每个索引都是一个优先级.我尝试了以下解决方案,

I'm trying to create a priority queue using an array of queues, each index of the array being a priority. I tried the following solution,

队列数据类型包含一个数组llist,

The queue data type contains an array llist,

Queue *q_create(int size)
{
struct queue *p;
struct q_head *h;
int i;

if ((p = (struct queue *)malloc(sizeof(struct queue))) != NULL) {
    p->size = size;
    for (i = 0; i < PRIODIFF; i++) {
        h = &(p->llist[i]);
        h->head = NULL;
        h->tail = NULL;
    }
}
return p;
}

我对这行感到困惑: h =&(p-> llist [i]); 我当时在想 llist [i] = h .这是用C编写的另一种方式吗?我将其读取为 h = llist [i] 的地址.这是正确的吗?

I'm confused by the line: h = &(p->llist[i]);I was thinking that llist[i] = h.Is this another way of writing it in C? I'm reading it as h = the address of llist[i].Is this correct?

谢谢

推荐答案

是的

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05-26 01:38