为什么这是错误的，如指针在c

问题描述

#include<stdio.h>
#include <string.h>
int main()
{
int *p1, *p2;
int ar[2];

p1=&ar[0];
p2=&ar[1];

printf( "%d\n",p2 - p1); // this is right

printf( "%d\n",p2 + p1); // why this is wrong

    return 0;
}

推荐答案

p4 =  p3+(p2-p1);

有效，因为它会增加p3的数量p2和p1之间的项目。



如果另外加上两个指针，你将添加两个地址，指向远离你分配的内存位置数组并且肯定是一个错误。

is valid as it does increment p3 by the number of items between p2 and p1.

If you add on the other hand two pointers you are adding two addresses which will point to a memory location far far away in your allocated array and is definitely an error.

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