问题描述
如标题中所述,我想要正则表达式,它将根据我的查询"按顺序给出结果.
as stated in heading I want regex which will give me results in order based on my 'query'.
line='VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'**
示例 1:
re.findall(r'FREQ="(.*?)"|VERSION="(.*?)"', line, re.MULTILINE)
输出为:
[('', 'OTHER'), ('OFF', '')]
我更喜欢的期望输出是这样的:
And desired output I prefer is something like:
['OFF', 'OTHER']
示例 2:
re.findall(r'VERSION="(.*?)"|FREQ="(.*?)"', line, re.MULTILINE)
输出是一样的:
[('', 'OTHER'), ('OFF', '')]
我更喜欢的期望输出是这样的:
And desired output I prefer is something like:
['OTHER', 'OFF']
有什么建议吗?
附言请不要问我想达到什么目的,并告诉我可能有更好的方法,除非您对此有疑问.
P.S.Please don't ask me what I want to achieve and tell me that there is maybe better way, only if you have some question regarding this.
谢谢!
推荐答案
您可以利用非捕获交替组来匹配 VERSION
或 FREQ
(可选地以一个词边界,看看它是否符合你的要求):
You may leverage a non-capturing alternation group to match either VERSION
or FREQ
(optionally preceded with a word boundary, just check if it meets your requirements):
\b(?:VERSION|FREQ)="(.*?)"
查看正则表达式演示
详情
\b
- 前导词边界(?:VERSION|FREQ)
-VERSION
或FREQ
="
-="
子字符串(.*?)
- 第 1 组(findall
的实际输出):除换行符以外的任何 0+ 个字符,尽可能少"
- 双引号.
\b
- a leading word boundary(?:VERSION|FREQ)
- eitherVERSION
orFREQ
="
- a="
substring(.*?)
- Group 1 (the actual output offindall
): any 0+ chars other than line break chars, as few as possible"
- a double quote.
查看 Python 演示:
import re
line='VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'
print(re.findall(r'\b(?:VERSION|FREQ)="(.*?)"', line))
# => ['OTHER', 'OFF']
也许更好的主意是捕获键值对并将它们映射到字典:
A better idea, perhaps, is to capture key-value pairs and map them to a dictionary:
import re
line = 'VERSION="OTHER" POWER="LOW" FREQ="OFF" MAXTUN="BLER"'
results = re.findall(r'(VERSION|FREQ)="(.*?)"', line)
print(dict(results))
# => {'FREQ': 'OFF', 'VERSION': 'OTHER'}
请参阅 Python 演示.
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