问题描述
我正在寻找代码wchich使用递归解析前缀表达式。主要是在C ++,但它可以在其他语言,我会翻译。感谢。
I am looking for code wchich parses prefix expressions using recursion. Primarily in C++, but it can bee in other language, i will translate. Thanks.
推荐答案
这很容易做自己(你只需要一个堆栈为运算符))。
It's really easy to do yourself (you just need a stack for the operators (and sometimes/optionally its first term)).
但是如果你真的不想做很多工作,这里有一个链接:
But if you really don't want to do much work, here's a link:
如果你需要使用递归,你基本上使用函数中的局部变量作为你的堆栈中的单个元素。
If you need to use recursion, you basically use local variables in the function as individual elements in your stack.
例如。伪C ++代码如下:
Eg. pseudo-C++ code follows:
int naughtyglobalendindex = 0;
int parse(string str) {
if (/* str starts off with an integer */) return the integer;
char operator;
operator = ?? // you will need to get the first op here. Maybe sscanf(str,"%c",&operator) or similar
// get first argument
int first = parse(/* str with 1st operator removed */);
// get 2nd integer argument
int second = parse(/* str - get substring from naughtyglobalendindex to end*/)
// return first operator second <- this is pseudocode
// in effect you want a switch clause
switch (operator) {
case '+': return first + second;
case '-': return first - second; // and so on
}
}
您可以将伪代码转换为实际的C ++,如果需要,修复全局 naughtyglobalendindex
变量。
You can convert the pseudocode to actual C++, and if you want, fix the global naughtyglobalendindex
variable if you want.
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