本文介绍了处理数据库中的数据的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想使用sql compact 3.5在C#中使用数据库,但是在每种形式中,与表相关的查询之一是执行我单击按钮并查看正确的结果,但是如果我更改条件并单击按钮,则查询在旧条件下执行,我看到旧结果表明sqlcashed旧数据
任何人都可以帮助我吗?
这是我的代码:
i want to work with data base in C# with sql compact 3.5 but in each form one of query that related with on table is execute i click on button and see the correct result butif i change the condition and click on button the query execute with the the old condition and i see the old result it peer that the sqlcashed the old data
any one can help me???
this my code:
private DataTable select(string con)
{
DataTable k = new System.Data.DataTable();
try
{
string str = "Data Source=C:\\Documents and Settings\\almas\\Desktop\\BazarKhodro\\khodro.sdf";
Qconnection.ConnectionString = str;
Qcommand.Connection = Qconnection;
Qcommand.Parameters.AddWithValue("@type", comboBox1 .Text );
Qcommand.Parameters.AddWithValue("@name", textBox3.Text);
Qcommand.Parameters.AddWithValue("@lname", textBox4.Text);
string commandText = " select kharid.date, moshtari.name, moshtari.lname, kharid.type, kharid.modelfrom, kharid.modelto, kharid.tip, kharid.karkardfrom, kharid.karkardto, kharid.color, kharid.pricefrom, kharid.priceto , kharid.parvande FROM kharid INNER JOIN moshtari ON kharid.mid = moshtari.id where "+con;
Qcommand.CommandText = commandText;
Qcommand.CommandType = CommandType.Text;
SqlCeDataAdapter a = new SqlCeDataAdapter();
a.SelectCommand = Qcommand;
a.Fill(k);
Qconnection.Open();
Qconnection.Close();
return k;
}
catch (Exception ex)
{
throw new Exception(ex.Message);
return k;
}
}
private void button1_Click(object sender, EventArgs e)
{
if (textBox3.Text == "" || textBox4.Text == "")
MessageBox.Show("لطفا نام و نام خانوادگي را وارد نماييد");
else
{
if (radioButton9.Checked == true)
{
string u = "moshtari.name like '%'+@name+'%' and moshtari.lname like '%'+@lname+'%' ";
dataGridView1.DataSource= select(u);
}
else if (radioButton8.Checked == true)
{
string u = "moshtari.name like '%'+@name+'%' and moshtari.lnamename like '%'+@lname+'%' and kharid.parvande=" + "'فعال'";
dataGridView1.DataSource = select(u);
}
else
{
string u = "moshtari.name like '%'+@name+'%' and moshtari.lnamename like '%'+@lname+'%' and kharid.parvande!=" + "'فعال'";
dataGridView1.DataSource = select(u);
}
}
}
推荐答案
private DataTable select(string con)
{
DataTable k = new System.Data.DataTable();
try
{
string str = "Data Source=C:\\Documents and Settings\\almas\\Desktop\\BazarKhodro\\khodro.sdf";
Qconnection.ConnectionString = str;
Qcommand.Connection = Qconnection;
Qcommand.Parameters.AddWithValue("@type", comboBox1 .Text );
Qcommand.Parameters.AddWithValue("@name", textBox3.Text);
Qcommand.Parameters.AddWithValue("@lname", textBox4.Text);
string commandText = " select kharid.date, moshtari.name, moshtari.lname, kharid.type, kharid.modelfrom, kharid.modelto, kharid.tip, kharid.karkardfrom, kharid.karkardto, kharid.color, kharid.pricefrom, kharid.priceto , kharid.parvande FROM kharid INNER JOIN moshtari ON kharid.mid = moshtari.id where "+con;
Qconnection.Open();
Qcommand.CommandText = commandText;
Qcommand.CommandType = CommandType.Text;
SqlCeDataAdapter a = new SqlCeDataAdapter(Qcommand);
a.Fill(k);
Qconnection.Close();
}
catch (Exception ex)
{
throw new Exception(ex.Message);
}
return k;
}
private void button1_Click(object sender, EventArgs e)
{
string u="";
if (textBox3.Text == "" || textBox4.Text == "")
MessageBox.Show("لطفا نام و نام خانوادگي را وارد نماييد");
else
{
if (radioButton9.Checked == true)
{
u = " moshtari.name like '%'+@name+'%' and moshtari.lname like '%'+@lname+'%' ";
}
else if (radioButton8.Checked == true)
{
u = "moshtari.name like '%'+@name+'%' and moshtari.lnamename like '%'+@lname+'%' and kharid.parvande=" + "'فعال'";
}
else
{
u = "moshtari.name like '%'+@name+'%' and moshtari.lnamename like '%'+@lname+'%' and kharid.parvande!=" + "'فعال'";
}
}
dataGridView1.DataSource= select(u);
dataGridView1.DataBind();
}
希望这能解决您的问题.
我认为您正面临问题,因为您没有绑定gridview.
Hope this will resolve your problem.
I think you are facing the problem because you are not binding the gridview.
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