！ for_in []中奇怪的双展开包装可选语法?

问题描述

之前我有一个，但答案却引出了另一个问题.是什么 ！?语法，我在其他任何地方都没有看到它，但这是我可以编译代码的唯一方法.有人可以告诉我什么！语法是什么意思?是虫子吗?该链接显示所有代码.

Earlier I had a question that I figured out, but the answer led to another question. What is the !? syntax, I haven't seen it anywhere else, but it was the only way I could get the code to compile. Can someone tell me what "!?" the syntax means? Is it a bug? The link shows all code.

field.superview!?.superview?.layer.borderWidth = 2

推荐答案

UIAlertController的textFields属性是[AnyObject]?.所以这就是你在做什么:

A UIAlertController's textFields property is an [AnyObject]?. So this is what you are doing:

let textFields : [AnyObject]? = [UIView()] // textFields is an Optional
for field in textFields! { // you unwrap the Optional, but now...
    // ... field is an AnyObject
    let v1 = field.superview // now v1 is a UIView?!
}

您看到问题了吗? AnyObject没有superview属性-或任何其他属性. Swift会允许这样做，但只会以将结果包装在Optional中为代价，因为这可能不是UIView，所以它可能不会响应superview(正如我解释此处).因此，现在它为您调用superview.但是superview本身会产生一个Optional(因为，如果这是一个UIView，则可能没有superview).因此是双重的Optional.

Do you see the problem? An AnyObject has no superview property - or any other properties. Swift will allow this, but only at the expense of wrapping the result in an Optional, because this might not be a UIView and so it might not respond to superview (as I explain here). So now it calls superview for you. But superview itself yields an Optional (because, if this is a UIView, it might have no superview). Hence the double Optional.

但是，如果您从一开始就进行铸造，那将不会发生:

But if you had cast to start with, that would not have happened:

for field in textFields as [UIView] {

现在field是一个UIView，向其发送superview消息是合法的，您只需要处理每个superview的单个展开即可.

Now field is a UIView and it is legal to send it the superview message, and you just have to deal with the single unwrapping of each superview.

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