问题描述
我在 UITableViewController
中有一个 UITableViewCell
.在我的单元格中有一个按钮,当您单击该按钮时,会将您带到另一个带有 prepareforsegue
的 view
.在 prepareForSegue
中,我这样做:
I've a UITableViewCell
in a UITableViewController
.In my cell there is a button that when you click takes you to another view
with a prepareforsegue
.In prepareForSegue
I do this:
if ([[segue identifier] isEqualToString:@"MySegue"])
{
UITableViewCell *cell = (UITableViewCell*) [[sender superview] superview];
UITableView *table = (UITableView*)[[[sender superview] superview] superview];
NSIndexPath *indexPath = [table indexPathForCell:cell];
}
好的!一切都一直运作良好.但是现在我已经用 iOS7 升级了 xCode,当我点击单元格中的按钮时,一个错误出现在我面前,我不知道如何解决它:
Ok! Everything has always worked well. But now that I've upgraded xCode with iOS7, when I click on the button located in the cell, an error presents itself to me, and I don't know how to solve it:
[UITableViewCell indexPathForCell:]: unrecognized selector sent to instance 0x9e160b0
2013-09-20 16:30:44.427 MyApp[8212:a0b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UITableViewCell indexPathForCell:]: unrecognized selector sent to instance 0x9e160b0'
*** First throw call stack:
(
0 CoreFoundation 0x024475e4 __exceptionPreprocess + 180
1 libobjc.A.dylib 0x01a5d8b6 objc_exception_throw + 44
2 CoreFoundation 0x024e4903 -[NSObject(NSObject) doesNotRecognizeSelector:] + 275
3 CoreFoundation 0x0243790b ___forwarding___ + 1019
4 CoreFoundation 0x024374ee _CF_forwarding_prep_0 + 14
5 MyApp 0x0004bc01 -[NewsTableViewController prepareForSegue:sender:] + 3441
6 UIKit 0x00af69cc -[UIStoryboardSegueTemplate _perform:] + 156
7 UIKit 0x00af6a59 -[UIStoryboardSegueTemplate perform:] + 115
8 libobjc.A.dylib 0x01a6f874 -[NSObject performSelector:withObject:withObject:] + 77
9 UIKit 0x005c4c8c -[UIApplication sendAction:to:from:forEvent:] + 108
10 UIKit 0x005c4c18 -[UIApplication sendAction:toTarget:fromSender:forEvent:] + 61
11 UIKit 0x006bc6d9 -[UIControl sendAction:to:forEvent:] + 66
12 UIKit 0x006bca9c -[UIControl _sendActionsForEvents:withEvent:] + 577
13 UIKit 0x006bbd4b -[UIControl touchesEnded:withEvent:] + 641
14 UIKit 0x00936d7f _UIGestureRecognizerUpdate + 7166
15 UIKit 0x00601d4a -[UIWindow _sendGesturesForEvent:] + 1291
16 UIKit 0x00602c6a -[UIWindow sendEvent:] + 1030
17 UIKit 0x005d6a36 -[UIApplication sendEvent:] + 242
18 UIKit 0x005c0d9f _UIApplicationHandleEventQueue + 11421
19 CoreFoundation 0x023d08af __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 15
20 CoreFoundation 0x023d023b __CFRunLoopDoSources0 + 235
21 CoreFoundation 0x023ed30e __CFRunLoopRun + 910
22 CoreFoundation 0x023ecb33 CFRunLoopRunSpecific + 467
23 CoreFoundation 0x023ec94b CFRunLoopRunInMode + 123
24 GraphicsServices 0x032c89d7 GSEventRunModal + 192
25 GraphicsServices 0x032c87fe GSEventRun + 104
26 UIKit 0x005c394b UIApplicationMain + 1225
27 MyApp 0x00002cfb main + 235
28 libdyld.dylib 0x01f42725 start + 0
29 ??? 0x00000001 0x0 + 1
)
libc++abi.dylib: terminating with uncaught exception of type NSException
应用崩溃的那一行是:
NSIndexPath *indexPath = [table indexPathForCell:cell]; }
推荐答案
在iOS7中UITableViewWrapperView
是UITableViewCell
的superview,意思是另一个您的超级视图:
In iOS7 UITableViewWrapperView
is the superview of UITableViewCell
, which means another superview for you:
iOS7:
UITableView *tableView = (UITableView *)cell.superview.superview;
iOS6"
UITableView *tableView = (UITableView *)cell.superview;
您可以在此处找到另一个更改:
Another change you can find it here:
似乎你的代码: UITableView table = (UITableView)[[[sender superview] superview] superview];返回一个 UITableViewCell
而不是 UITableView
.
seems your code: UITableView table = (UITableView)[[[sender superview] superview] superview]; returns a UITableViewCell
not a UITableView
.
试试下面的方法:
UITableView *table = (UITableView*)[[[[[sender superview] superview] superview] superview] superview];
这篇关于iOS7 中的 UITableViewCell indexPath 崩溃的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持!