问题描述
如何使用 selenium 的 find_elements_by_xpath() 基于文本，当它可能有也可能没有词时?
How can I use selenium's find_elements_by_xpath() based on text, when it may or may not have a word?
示例:它可以是 #1 here 或 #1 here.我希望两者都属于同一个列表，因为该 func 返回一个列表.ATM 我有 driver.find_elements_by_xpath("//*[contains(text(), '#1 here')]") 但这只会找到第一种情况，而不是那些带有是.基本上，类似于 driver.find_elements_by_xpath("//*[contains(text(), '#1 here' or '#1 is here')]")
Example: it can be either #1 here or #1 is here. I want both to be part of the same list, since that func return a list. ATM I have driver.find_elements_by_xpath("//*[contains(text(), '#1 here')]") but that would only find the first case, not the ones with an is. Basically, something like driver.find_elements_by_xpath("//*[contains(text(), '#1 here' or '#1 is here')]")
我怎么能这样做?
我也在努力保持他们的秩序"；所以，从上到下的第一个是列表中的#1，等等
I'm also trying to keep their "order"So, first one from top to bot is #1 on list, etc
我可以做 2 个不同的列表，每个列表一个，然后将它们组合起来，但这也会搞砸
I could do 2 different lists, one for each and then combine them but that would also screw that up
推荐答案
您可以使用 or 子句，您可以使用以下任一 xpath 基于 定位器策略:
You can use the or clause you can use either of the following xpath based Locator Strategies:
Selenium3:
driver.find_elements_by_xpath("//*[contains(., 'this') or contains(., 'or this')]")
Selenium4:
driver.find_elements(By.XPATH, "//*[contains(., 'this') or contains(., 'or this')]")
这篇关于Selenium 的 find_elements 带有两个文本子句?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！