我有个问题

问题描述

我有一个问题：


以下代码中j的值是多少？为什么会这样？


int i;

for（i = 0; i< 1; i ++）

{

开关（i）

{

案例0：i + = 5;

案例3：我+ = 3;

案例5：i + = 5;

休息;

}

}

int j = i;

I have a question:

What will be the value of j in the following code? and why is it so?

int i;
for( i = 0; i < 1; i++ )
{
switch( i )
{
case 0: i += 5;
case 3: i += 3;
case 5: i += 5;
break;
}
}
int j = i;

推荐答案

对于C90，没有：这是一个错误。对于C99，您怎么看？


-

Thad

For C90, nothing: it is an error. For C99, what do you think?

--
Thad

i = 5 here（no break）

i = 5 here (no break)

i = 8 here（no break）

i = 8 here (no break)

i = 13 here

i = 13 here

i = 14 here（13 + 1）

i = 14 here (13 + 1)

所以j = 14


问候奥拉夫

so j = 14

Greetings Olaf

i = 5 here（no break）case 3：i + = 3;


i = 8 here（no break）案例5：i + = 5;

i = 13这里

i = 5 here (no break) case 3: i += 3;

i = 8 here (no break) case 5: i += 5;
i = 13 here

i = 14 here（13 + 1）

i = 14 here (13 + 1)

所以j = 14


问候Olaf

so j = 14

Greetings Olaf

我问的是当它落空时，案例3如何执行？

当时i的值是5。或者它只是执行所有语句，直到看到下一个中​​断的
，无论案例陈述是什么？我知道这是一个基本的问题。我只想要一个解释。


谢谢。

what i was asking is when it falls through, how can case 3: execute?
value of i is 5 at that time. Or it just executes all statements until
a next break is seen, regardless of the case statements? I know its a
basic question. I just want an explanation.

Thanks.

这篇关于我有个问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！