问题描述
来自MFC，我处理 qDebug（）很像 TRACE（），假设它从由预处理器释放构建（在MFC中，它使用 #define TRACE 1？（void *）0：AfxTrace ）完成。
Coming from MFC, I treated qDebug() much like TRACE(), assuming that it is removed from Release builds by the preprocessor (in MFC it's done using #define TRACE 1 ? (void*) 0 : AfxTrace).
然而，令我惊讶的是， qDebug（）也在发行版本中执行。如何更改这个？而且，为什么这样，Qt背后的开发者的推理是什么呢？
To my surprise, however, qDebug() is executed in Release builds as well. How do I change this? And also, why is this so, what was the reasoning of the developers of Qt behind this decision?
推荐答案
qDebug 也是预处理器控制的，但它有自己的特殊宏 QT_NO_DEBUG_OUTPUT 。如果您将它添加到您的版本构建定义，它将被删除。
qDebug is also preprocessor-controlled, but it has its own special macro, QT_NO_DEBUG_OUTPUT. If you add that to your Release build defines, it will be removed.
这篇关于为什么qDebug在Release版本中工作？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！