我怎样才能从输入字符串，不包括使用与fgets一个换行符？

问题描述

我想在其他地方写输入的字符串，不知道如何与出现与此字符串，我用标准输入和与fgets收购的一部分，新的生产线做了。

I'm trying to write an inputted string elsewhere and do not know how to do away with the new line that appears as part of this string that I acquire with stdin and fgets.

 char buffer[100];
 memset(buffer, 0, 100);
 fgets(buffer, 100, stdin);
 printf("buffer is: %s\n stop",buffer);

我试图限制数据的获取与fgets以及限制多少数据被写入但新线保持量。我怎么能简单地得到所输入的字符串，最多有没有别的写的最后一个字符？

I tried to limit the amount of data that fgets gets as well as limiting how much of the data is written but the new line remains. How can I simply get the inputted string up to the last character written with nothing else?

推荐答案

尝试

fgets(buffer, 100, stdin);
size_t ln = strlen(buffer)-1;
if (buffer[ln] == '\n')
    buffer[ln] = '\0';

这篇关于我怎样才能从输入字符串，不包括使用与fgets一个换行符？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持！